import sys # sys.setrecursionlimit(200005) int1 = lambda x: int(x)-1 p2D = lambda x: print(*x, sep="\n") def II(): return int(sys.stdin.readline()) def LI(): return list(map(int, sys.stdin.readline().split())) def LLI(rows_number): return [LI() for _ in range(rows_number)] def LI1(): return list(map(int1, sys.stdin.readline().split())) def LLI1(rows_number): return [LI1() for _ in range(rows_number)] def SI(): return sys.stdin.readline().rstrip() # dij = [(0, 1), (-1, 0), (0, -1), (1, 0)] # dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)] # inf = 18446744073709551615 inf = 4294967295 md = 10**9+7 # md = 998244353 def add(s, i): u = 0 for c in s: if c not in trie[u]: trie[u][c] = len(trie) trie.append({}) vv.append(0) u = trie[u][c] vv[u] |= 1 << i trie[u]["end"] = s def search(s): bb, dd = [], [] u = 0 d = 0 now = -1 for c in s: u = trie[u][c] d += 1 if vv[u] != now: now = vv[u] bb.append(now) dd.append(d) return bb, dd def nHr(hn, hr): return nCr(hn+hr-1, hr-1) def nPr(com_n, com_r): if com_r < 0: return 0 if com_n < com_r: return 0 return fac[com_n]*ifac[com_n-com_r]%md def nCr(com_n, com_r): if com_r < 0: return 0 if com_n < com_r: return 0 return fac[com_n]*ifac[com_r]%md*ifac[com_n-com_r]%md # 準備 n_max = 200005 fac = [1] for i in range(1, n_max+1): fac.append(fac[-1]*i%md) ifac = [1]*(n_max+1) ifac[n_max] = pow(fac[n_max], md-2, md) for i in range(n_max-1, 1, -1): ifac[i] = ifac[i+1]*(i+1)%md trie = [{}] vv = [0] n = II() ss = [SI()+"@" for _ in range(n)] for i, s in enumerate(ss): add(s, i) bbs, dds = [], [] for i, s in enumerate(ss): bb, dd = search(s) bbs.append(bb) dds.append(dd) popcnt = lambda x: bin(x).count("1") dp = [0]*(1 << n) ans = [0]*(n+1) for bit in range((1 << n)-1)[::-1]: k = n-popcnt(bit) for i, s in enumerate(ss): if bit >> i & 1: continue nbit = bit | 1 << i cost = 0 for b, d in zip(bbs[i], dds[i]): if bit & b == 0: cost = d break dp[bit] += dp[nbit]+cost dp[bit] = dp[bit]*pow(k, md-2, md)%md ans[k] += dp[bit] for k in range(1, n+1): ans[k] *= fac[k] ans[k] %= md print(*ans[1:], sep="\n")