#include "atcoder/all"
#include <iostream>
#include <cstdio>
#include <string>
#include <cstring>
#include <deque>
#include <list>
#include <queue>
#include <stack>
#include <vector>
#include <utility>
#include <algorithm>
#include <map>
#include <set>
#include <complex>
#include <cmath>
#include <limits>
#include <climits>
#include <ctime>
#include <cassert>
#include <numeric>
#include <functional>
#include <bitset>
#include <cstddef>
#include <type_traits>
#include <vector>

using namespace std;
const long long int INF = numeric_limits<long long int>::max() / 4;
const int inf = numeric_limits<int>::max() / 4;
const long long int MOD1000000007 = 1000000007;
const long long int MOD998244353 = 998244353;
const double MATH_PI = 3.1415926535897932;

template<typename T1, typename T2>
inline void chmin(T1 &a, const T2 &b) { if (a > b) a = b; }

template<typename T1, typename T2>
inline void chmax(T1 &a, const T2 &b) { if (a < b) a = b; }

#define lint long long int
#define ALL(a) a.begin(),a.end()
#define RALL(a) a.rbegin(),a.rend()
#define rep(i, n) for(int i=0;i<(int)(n);i++)
#define VI vector<int>
#define VLL vector<long long>
#define VC vector<char>
#define VB vector<bool>
#define PI pair<int, int>
#define PLL pair<long long, long long>
#define VPI vector<pair<int, int>>
#define VPLL vector<pair<long long, long long>>
#define VVI vector<vector<int>>
#define VVPI vecor<vector<pair<int, int>>>
#define VVPILL vector<vector<pair<int, long long>>>

#define SUM(v) accumulate(ALL(v), 0LL)
#define MIN(v) *min_element(ALL(v))
#define MAX(v) *max_element(ALL(v))

using mint = atcoder::modint998244353;

int main() {

    int n; cin >> n;
    string s; cin >> s;
    vector<vector<vector<mint>>> dp(n + 1, vector<vector<mint>>(2, vector<mint>(2, 0)));
    dp[0][0][0] = 1;
    for (int i = 0; i < n; i++) {
        for (int f1 = 0; f1 < 2; f1++) {
            for (int f2 = 0; f2 < 2; f2++) {
                // 何を使うか
                for (char c = 'a'; c <= 'z'; c++) {
                    if (!f1 and c > s[i]) continue;
                    if (f2 and c == 'a') continue;
                    int nf1 = (f1 or c < s[i]) ? 1 : 0;
                    int nf2 = (f2 or c == 'a') ? 1 : 0;
                    dp[i + 1][nf1][nf2] += dp[i][f1][f2];
                }
            }
        }
    }
    cout << dp[n][1][1].val() << endl;
    return 0;
}