#include using namespace std; #define ll long long #define rep(i,n) for(int i=0;i=0;i--) #define rrep2(i,n,k) for(int i=n-1;i>=n-k;i--) #define vll(n,i) vector(n,i) #define v2ll(n,m,i) vector>(n,vll(m,i)) #define v3ll(n,m,k,i) vector>>(n,v2ll(m,k,i)) #define v4ll(n,m,k,l,i) vector>>>(n,v3ll(m,k,l,i)) #define all(v) v.begin(),v.end() #define chmin(k,m) k = min(k,m) #define chmax(k,m) k = max(k,m) #define Pr pair #define Tp tuple #define riano_ std::ios::sync_with_stdio(false);std::cin.tie(nullptr) using Graph = vector>; #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") const ll mod = 998244353; template struct modint{ uint64_t val; constexpr modint(const int64_t val_=0) noexcept:val((val_%int64_t(mod)+int64_t(mod))%int64_t(mod)){} constexpr modint operator-() const noexcept{ return modint(*this)=mod-val; } constexpr modint operator+(const modint rhs) const noexcept{ return modint(*this)+=rhs; } constexpr modint operator-(const modint rhs) const noexcept{ return modint(*this)-=rhs; } constexpr modint operator*(const modint rhs) const noexcept{ return modint(*this)*=rhs; } constexpr modint operator/(const modint rhs) const noexcept{ return modint(*this)/=rhs; } constexpr modint &operator+=(const modint rhs) noexcept{ val+=rhs.val; val-=((val>=mod)?mod:0); return (*this); } constexpr modint &operator-=(const modint rhs) noexcept{ val+=((val>=1; } return (*this)*=now; } modint & operator++(){ val++; if (val == mod) val = 0; return *this; } modint operator++(int){ modint res = *this; ++*this; return res; } constexpr bool operator==(const modint rhs) noexcept{ return val==rhs.val; } constexpr bool operator!=(const modint rhs) noexcept{ return val!=rhs.val; } friend constexpr ostream &operator<<(ostream& os,const modint x) noexcept{ return os<<(x.val); } friend constexpr istream &operator>>(istream& is,modint& x) noexcept{ uint64_t t; is>>t,x=t; return is; } }; typedef modint mint; mint pw(long long a,long long b,long long m = mod){ if(a%m==0) return mint(0); if(b==0) return mint(1); else if(b%2==0){ long long x = pw(a,b/2,m).val; return mint(x*x); } else{ long long x = pw(a,b-1,m).val; return mint(a*x); } } mint modinv(long long a, long long m = mod) { long long b = m, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } u %= m; return mint(u); } #define vm(n,i) vector(n,i) #define v2m(n,m,i) vector>(n,vm(m,i)) #define v3m(n,m,k,i) vector>>(n,v2m(m,k,i)) #define v4m(n,m,k,l,i) vector>>>(n,v3m(m,k,l,i)) //binary trie (dynamic segtree version) class binary_trie { public: ll n; ll len; vector> to; vector content; vector count; //vector sum; //vector lis; vector emp = {-1,-1}; binary_trie(ll k){ n = 1; len = k; to.push_back(emp); content.push_back(0); count.push_back(0); //sum.push_back(0); } //0-1のvectorに変換 vector convert(ll x){ vector c; for(int i=0;i<=len;i++){ c.push_back(x%2); x /= 2; } return c; } mint size(void){ return count[0]; } //xを追加する 既に存在していたらtrue bool insert(ll x,int cc = 1){ bool ex = true; auto p = convert(x); int now = 0; count[now] += cc; //sum[now] += mint(x)*cc; for(int i=len-1;i>=0;i--){ bool found = false; if(to[now][p[i]]!=-1){ found = true; now = to[now][p[i]]; count[now] += cc; //sum[now] += mint(x)*cc; } if(found) continue; ex = false; to[now][p[i]] = n; to.push_back(emp); content.push_back(p[i]); count.push_back(cc); //sum.push_back(mint(x)*cc); now = n; n++; } return ex; } //k以下の数の個数 int count_under(int k){ insert(k,0); auto p = convert(k); int now = 0; int res = 0; for(int i=len-1;i>=0;i--){ if(p[i]==1&&to[now][0]!=-1){ res += count[to[now][0]]; } now = to[now][p[i]]; } res += count[now]; return res; } int binary_src(int k){ auto p = convert(k); int now = 0; int res = 0; int num = 0; for(int i=len-1;i>=0;i--){ //cout << now << endl; if(i==0){ res += count[now]; if(num-res==k){ return num; } else if(num-res==k-1){ return num+1; } } else if(to[now][0]==-1){ if(res+num+(1LL<<(i-1))-1>=k){ return k-res; } else if(to[now][1]!=-1){ now = to[now][1]; continue; } else{ return k-(res+count[to[now][0]]); } } else{ if(res+num+(1LL<<(i-1))-1+count[to[now][0]]>=k){ now = to[now][0]; } else{ if(to[now][1]!=-1){ res += count[to[now][0]]; num += (1LL<<(i-1)); now = to[now][1]; } else{ return k-(res+count[to[now][0]]); } } } } return res; } }; binary_trie bt(31); int main() { riano_; ll ans = 0; ll K; cin >> K; if(K%5==0){ cout << "AE" << endl; cout << "B" << endl; cout << "C" << endl; cout << "D" << endl; } if(K%5==1){ cout << "E" << endl; cout << "BA" << endl; cout << "C" << endl; cout << "D" << endl; } if(K%5==2){ cout << "E" << endl; cout << "A" << endl; cout << "CB" << endl; cout << "D" << endl; } if(K%5==3){ cout << "E" << endl; cout << "A" << endl; cout << "B" << endl; cout << "DC" << endl; } if(K%5==4){ cout << "ED" << endl; cout << "A" << endl; cout << "B" << endl; cout << "C" << endl; } //cout << ans << endl; }