T = gets.to_i

T.times do
  n = gets.to_i
  a = gets.split.map(&:to_i)
  b = gets.split.map(&:to_i)

  if a[0] != b[0] || a.sort != b.sort
    puts 'No'
  else
    if 3.step(n, 2).all? { |i| 2 * i <= n || a[i - 1] == b[i - 1] }
      puts 'Yes'
    else
      puts 'No'
    end
  end
end