// No.1778 括弧列クエリ / Bracketed Sequence Query #include using namespace std; struct LCA { vector r, p, d, t, q; LCA(const vector> &e, int root = 0) : t(e.size()), d(e.size()), q(e.size() * 2) { int n = e.size(), tick = 0; function dfs = [&](int u, int par) { t[u] = tick++; for (auto v : e[u]) if (v != par) d[v] = d[u] + 1, p.push_back(u), r.push_back(t[u]), dfs(v, u); }; dfs(root, -1); for (int i = 0; i < r.size(); i++) { q[i + n] = r[i]; for (int j = i + n; j /= 2; ) q[j] = min(q[j * 2], q[j * 2 + 1]); } } int rmq(int l, int r) { int n = q.size() / 2, a = INT_MAX, b = INT_MAX; for (int i = l + n, j = r + n; i < j; i /= 2, j /= 2) { if (i % 2) a = min(a, q[i++]); if (j % 2) b = min(b, q[--j]); } return min(a, b); } int lca(int u, int v) { return u == v ? u : p[rmq(min(t[u], t[v]), max(t[u], t[v]))]; } }; int main(int argc, char *argv[]) { cin.tie(0)->sync_with_stdio(0); int n, q; string s; cin >> n >> q >> s; s = "(" + s + ")"; n += 1; vector p(n), st; for (int i = 0; i < n; i++) if (s[i] == '(') st.push_back(i); else p[i] = st.back(), p[st.back()] = i, st.pop_back(); vector> g(n); function build = [&](int u, int c) { if (c <= 2) return; for (int v = u + 1; v < u + c && p[v] > v; v = p[v] + 1) g[u].push_back(v), build(v, p[v] - v + 1); }; build(0, n); auto lca = LCA(g); while (q--) { int x, y; cin >> x >> y; auto t = lca.lca(min(x, p[x]), min(y, p[y])); if (t == 0) cout << -1 << "\n"; else cout << t << ' ' << p[t] << "\n"; } return 0; }