use std::io::Read; fn get_word() -> String { let stdin = std::io::stdin(); let mut stdin=stdin.lock(); let mut u8b: [u8; 1] = [0]; loop { let mut buf: Vec = Vec::with_capacity(16); loop { let res = stdin.read(&mut u8b); if res.unwrap_or(0) == 0 || u8b[0] <= b' ' { break; } else { buf.push(u8b[0]); } } if buf.len() >= 1 { let ret = String::from_utf8(buf).unwrap(); return ret; } } } #[allow(dead_code)] fn get() -> T { get_word().parse().ok().unwrap() } fn powmod(x: i64, mut e: i64, m: i64) -> i64 { let mut sum = 1; let mut cur = x % m; while e > 0 { if e % 2 != 0 { sum = sum * cur % m; } cur = cur * cur % m; e /= 2; } sum } const MOD: i64 = 1_000_000_007; // https://yukicoder.me/problems/no/1419 (3) // あり得る offset とその確率は、-2^K+1 + (0 から 2^{K+1} - 2 までの偶数の一様分布に従う変数) である。 fn main() { let n: usize = get(); let k: i64 = get(); let x = powmod(2, k, n as i64); let base = powmod(2, MOD - 1 - k, MOD); let x = (n + 1 - x as usize) % n; let m = if n % 2 == 0 { n / 2 } else { n }; let r = powmod(2, k, m as i64); let q = (powmod(2, k, MOD) + MOD - r) * powmod(m as i64, MOD - 2, MOD) % MOD; let mut ans = vec![0; n]; for i in 0..m { if i < r as usize { ans[(x + 2 * i) % n] = (q + 1) * base % MOD; } else { ans[(x + 2 * i) % n] = q * base % MOD; } } for i in 0..n { println!("{}", ans[i]); } }