def solve(n, a, b):
    from collections import Counter
    ans = []
    minb, cnt = Counter(a + b).most_common()[0]
    if cnt > 1 and minb not in a:
        p = a.index(max(a))
        q = b.index(minb)
        ans.append((1, p + 1, q + 1))
        ans.append((2, p + 1, q + 1))
        ans.append((1, p + 1, q + 1))
        a[p], b[q] = b[q], a[p]
    if cnt > 1 and minb not in b:
        p = a.index(minb)
        q = b.index(min(b))
        ans.append((1, p + 1, q + 1))
        ans.append((2, p + 1, q + 1))
        ans.append((1, p + 1, q + 1))
        a[p], b[q] = b[q], a[p]
    times = a.count(minb) + b.count(minb)
    cnt0 = 0
    while times > 1 and cnt0 < n:
        cnt0 += 1
        times -= 1
        if b.count(minb) > 1:
            p = a.index(minb)
            q = b.index(minb)
            ans.append((2, p + 1, q + 1))
            b[q] = 0
        elif a.count(minb) >= 1:
            p = a.index(minb)
            q = b.index(minb)
            ans.append((1, p + 1, q + 1))
            a[p] = 0
    while max(a) >= min(b):
        p = a.index(max(a))
        q = b.index(min(b))
        if min(b) == 0:
            ans.append((2, p + 1, q + 1))
            ans.append((1, p + 1, q + 1))
            a[p], b[q] = b[q], a[p]
        elif max(a) == min(b):
            ans.append((1, p + 1, q + 1))
            a[p] = 0
        else:
            ans.append((1, p + 1, q + 1))
            ans.append((2, p + 1, q + 1))
            ans.append((1, p + 1, q + 1))
            a[p], b[q] = b[q], a[p]
    return ans
            




n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
ans = solve(n, a, b)
print(len(ans))
for i in range(n):
    for j in range(n):
        if a[i] >= b[j]:
            print(a[i], b[j])
            raise Exception
for t, i, j in ans:
    print(t, i, j)