import sys
input = sys.stdin.readline

"""
強連結成分分解（SCC）
from : https://github.com/ryusuke920/kyopro_educational_90_python/blob/main/solve_python/021.py
ref : https://manabitimes.jp/math/1250
"""

class SCC:
	def __init__(self, n):
		self.n = n
		self.graph = [[] for _ in range(n)]
		self.rev_graph = [[] for _ in range(n)]
		self.labels = [-1] * n
		self.lb_cnt = 0
	
	#グラフに有向辺を追加（逆向きのものを含む）
	def add_edge(self, v, nxt_v):
		self.graph[v].append(nxt_v)
		self.rev_graph[nxt_v].append(v)

	#SCCグラフの構成
	def build(self):
		self.post_order = []
		self.used = [False] * self.n
		for v in range(self.n):
			if(not self.used[v]):
				self._dfs(v)
		for v in reversed(self.post_order):
			if(self.labels[v] == -1):
				self._rev_dfs(v)
				self.lb_cnt += 1

	#SCCグラフを作る上でのDFS
	def _dfs(self, v):
		stack = [v, 0]
		while(stack):
			v, idx = stack[-2:]
			if not idx and self.used[v]:
				stack.pop()
				stack.pop()
			else:
				self.used[v] = True
				if idx < len(self.graph[v]):
					stack[-1] += 1
					stack.append(self.graph[v][idx])
					stack.append(0)
				else:
					stack.pop()
					self.post_order.append(stack.pop())

	#逆向きDFS
	def _rev_dfs(self, v):
		stack = [v]
		self.labels[v] = self.lb_cnt
		while stack:
			v = stack.pop()
			for nxt_v in self.rev_graph[v]:
				if self.labels[nxt_v] != -1:
					continue
				stack.append(nxt_v)
				self.labels[nxt_v] = self.lb_cnt

	#構成し終えたSCCグラフを連結成分ごとにリストにする
	def construct(self):
		self.dag = [[] for i in range(self.lb_cnt)]
		self.groups = [[] for i in range(self.lb_cnt)]
		for v, lb in enumerate(self.labels):
			for nxt_v in self.graph[v]:
				nxt_lb = self.labels[nxt_v]
				if lb == nxt_lb:
					continue
				self.dag[lb].append(nxt_lb)
			self.groups[lb].append(v)
		return self.dag, self.groups


"""
Main Code
"""

n,m = map(int, input().split())
scc = SCC(n)
for _ in [0] * m:
	a,b = map(int, input().split())
	a -= 1;	b -= 1
	scc.add_edge(a,b)
scc.build()
dag,_ = scc.construct()

t = len(dag)
if(t == 1):
	print(0)
	exit(0)

source = [True] * t
sink = [True] * t
for i in range(t):
	for j in dag[i]:
		sink[i] = source[j] = False

ans = max(sum(source),sum(sink))
print(ans)