import sys
#input = sys.stdin.readline #文字列につけてはダメ
input = sys.stdin.buffer.readline #文字列につけてはダメ
#sys.setrecursionlimit(1000000)
#import bisect
#import itertools
#import random
from heapq import heapify, heappop, heappush
#from collections import defaultdict 
#from collections import deque
#import copy
#import math
#from functools import lru_cache
#MOD = pow(10,9) + 7
#MOD = 998244353


def main():
    N,M,K = map(int,input().split())
    R = list(map(int,input().split()))
    R = [r-1 for r in R]
    R.sort()
    dic = {}
    req = 0
    G = [[] for _ in range(N)]
    for i in range(M):
        a,b,c = map(int,input().split())
        a -= 1; b -= 1
        G[a].append((c,b))
        G[b].append((c,a))
        if req < K and i == R[req]:
            dic[(a,b)] = req
            dic[(b,a)] = req
            req += 1
    #print(dic)

    dis = dijkstra_heap2(0,K,G,dic)
    ans = dis[-1]
    print(ans)

def dijkstra_heap2(s,K,G,dic):
    INF = pow(10,18)
    #S:start, V: node, E: Edge, G: Graph
    V = len(G)
    K2 = 1 << K
    #d[i][j]: i番目の頂点にいて通った道の状態がjの時の最短経路
    #idx = i * K2 + j 
    d = [INF for _ in range(V * K2)]
    d[s] = 0
    PQ = []
    heappush(PQ,(0,s))

    while PQ:
        c,vidx = heappop(PQ)
        vi = vidx // K2
        vj = vidx % K2
        if d[vidx] < c:
            continue
        d[vidx] = c
        if vidx == V*K2 - 1:
            print(c);exit()
        for cost,ui in G[vi]:
            uj = vj
            if (vi,ui) in dic:
                uj = vj | 1 << dic[(vi,ui)]
            uidx = ui * K2 + uj
            if d[uidx] <= cost + d[vidx]:
                continue
            d[uidx] = cost + d[vidx]
            heappush(PQ,(d[uidx], uidx))

    return d

if __name__ == '__main__':
    main()