#include #include using namespace std; using namespace atcoder; using mint = modint1000000007; const int mod = 1000000007; //using mint = modint998244353; //const int mod = 998244353; //const int INF = 1e9; //const long long LINF = 1e18; #define rep(i, n) for (int i = 0; i < (n); ++i) #define rep2(i,l,r)for(int i=(l);i<(r);++i) #define rrep(i, n) for (int i = (n-1); i >= 0; --i) #define rrep2(i,l,r)for(int i=(r-1);i>=(l);--i) #define all(x) (x).begin(),(x).end() #define allR(x) (x).rbegin(),(x).rend() #define endl "\n" #define P pair template inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; } template inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n; cin >> n; if (n < 4) { cout << 0 << endl; return 0; } vector> dp(n - 2, vector(8)); rep(i, 8)dp[0][i] = 1; rep(i, dp.size() - 1) { rep(j, 8) { int nj = (j % 4) * 2; dp[i + 1][j] = dp[i][nj] + dp[i][nj + 1]; } dp[i + 1][5] -= dp[i][2]; } mint ans = pow_mod(2, n, mod); rep(i, 8)ans -= dp[n - 3][i]; cout << ans.val() << endl; return 0; }