#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(ll i=0;i<n;i++)
#define repl(i,l,r) for(ll i=(l);i<(r);i++)
#define per(i,n) for(ll i=(n)-1;i>=0;i--)
#define perl(i,r,l) for(ll i=r-1;i>=l;i--)
#define fi first
#define se second
#define pb push_back
#define ins insert
#define pqueue(x) priority_queue<x,vector<x>,greater<x>>
#define all(x) (x).begin(),(x).end()
#define CST(x) cout<<fixed<<setprecision(x)
#define vtpl(x,y,z) vector<tuple<x,y,z>>
#define rev(x) reverse(x);
using ll=long long;
using vl=vector<ll>;
using vvl=vector<vector<ll>>;
using pl=pair<ll,ll>;
using vpl=vector<pl>;
using vvpl=vector<vpl>;
const ll MOD=1000000007;
const ll MOD9=998244353;
const int inf=1e9+10;
const ll INF=4e17;
const ll dy[9]={0,1,-1,0,1,1,-1,-1,0};
const ll dx[9]={1,0,0,-1,1,-1,1,-1,0};
template<class T> inline bool chmin(T& a, T b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}
template<class T> inline bool chmax(T& a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}


const int mod = 1000000007;
const int max_n = 200005;
struct mint {
  ll x; // typedef long long ll;
  mint(ll x=0):x((x%mod+mod)%mod){}
  mint operator-() const { return mint(-x);}
  mint& operator+=(const mint a) {
    if ((x += a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator-=(const mint a) {
    if ((x += mod-a.x) >= mod) x -= mod;
    return *this;
  }
  mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
  mint operator+(const mint a) const { return mint(*this) += a;}
  mint operator-(const mint a) const { return mint(*this) -= a;}
  mint operator*(const mint a) const { return mint(*this) *= a;}
  mint pow(ll t) const {
    if (!t) return 1;
    mint a = pow(t>>1);
    a *= a;
    if (t&1) a *= *this;
    return a;
  }
  bool operator==(const mint &p) const { return x == p.x; }
  bool operator!=(const mint &p) const { return x != p.x; }
  // for prime mod
  mint inv() const { return pow(mod-2);}
  mint& operator/=(const mint a) { return *this *= a.inv();}
  mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
using vm=vector<mint>;
using vvm=vector<vm>;
struct combination {
  vector<mint> fact, ifact;
  combination(int n):fact(n+1),ifact(n+1) {
    assert(n < mod);
    fact[0] = 1;
    for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
    ifact[n] = fact[n].inv();
    for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
  }
  mint operator()(int n, int k) {
    if (k < 0 || k > n) return 0;
    return fact[n]*ifact[k]*ifact[n-k];
  }
}comb(max_n);


//O(N^3logk)
//https://yukicoder.me/submissions/733933
//https://atcoder.jp/contests/abc236/submissions/28778130
using vec=vector<mint>;
using matrix=vector<vector<mint>>;
matrix matmul(matrix &left,matrix &right){
    int n=left.size();
    matrix ret(n,vec(n));//+の単位元で埋める
    for(int i=0;i<n;i++){
        for(int k=0;k<n;k++){//ループ順序の最適化
            for(int j=0;j<n;j++){
                ret[i][j]+=left[i][k]*right[k][j];
            }
        }
    }
    return ret;
}
matrix matpow(matrix &mat,ll k){
    int n=mat.size();
    matrix ret(n,vec(n));//+の単位元で埋める
    for(int i=0;i<n;i++)ret[i][i]=1;//*の単位元で埋める
    while(k){
        if(k&1)ret=matmul(mat,ret);
        k>>=1;
        if(k)mat=matmul(mat,mat);
    }
    return ret;
}
vec update(matrix &mat,vec &v){
    int n=mat.size();
    vec ret(n);//+の単位元で埋める
    for(int i=0;i<n;i++){
        for(int j=0;j<n;j++){
            ret[i]+=mat[i][j]*v[j];
        }
    }
    return ret;
}
mint calc1(ll n,ll k){
    return mint(k)*mint(k-1).pow(n-1);
}
mint calc2(ll n,ll k){
    mint p=(k-2)*(k-2)+k-1;
    return mint(k*(k-1))*p.pow(n-1);
}
mint calc(ll n,ll k,ll m){//縦nマスのグリッドをk色で塗り切る
    if(m==1)return calc1(n,k);
    if(m==2)return calc2(n,k);
    if(k<2)return 0;
    if(k==2)return 2;
    vvm mat(2,vm(2));
    mat[0][0]=mint(k-1)+mint(k-2)*mint(k-2);
    mat[1][0]=mint(k-1)*mint(k-1)+mint(k-2)*mint(k-2)*mint(k-2);
    mat[1][0]-=mat[0][0];
    mat[0][1]=mint(k-2)*2+mint(k-3)*mint(k-3);
    mat[1][1]=mint(k-2)*mint(k-1)*2+mint(k-3)*mint(k-2)*mint(k-2);
    mat[1][1]-=mat[0][1];
    auto ans=matpow(mat,n-1);
    vec dp(2);dp[0]=k*(k-1);dp[1]=k*(k-1)*(k-2);
    dp=update(ans,dp);
    return dp[0]+dp[1];
}
int main(){
    ll n,m,k;cin >> n >> m >> k;
    mint ans=0;
    for(int i=0;i<=k;i++){
        mint ret=calc(m,i,n)*comb(k,i);
        if((k-i)&1)ans-=ret;
        else ans+=ret;
    }
    cout << ans << endl;
}