#include using namespace std; using ll = long long; using VI = vector; using P = pair; #define REP(i, n) for (int i = 0; i < (int)(n); i++) #define FOR(i, a, b) for (ll i = a; i < (ll)(b); i++) #define ALL(a) (a).begin(),(a).end() constexpr int INF = 1001001001; constexpr ll LINF = 1001001001001001001ll; constexpr int DX[] = {1, 0, -1, 0}; constexpr int DY[] = {0, 1, 0, -1}; template< typename T1, typename T2> inline bool chmax(T1 &a, T2 b) {return a < b && (a = b, true); } template< typename T1, typename T2> inline bool chmin(T1 &a, T2 b) {return a > b && (a = b, true); } const ll MOD = 998244353; vector f(200001, 1); ll mod_pow(ll x, ll n, ll mod) { ll res = 1; while (n > 0) { if (n & 1) res = res * x % mod; x = x * x % mod; n >>= 1; } return res; } ll C(ll n, ll k) { return f[n] * mod_pow(f[k], MOD - 2, MOD) % MOD * mod_pow(f[n - k], MOD - 2, MOD) % MOD; } int main() { REP(i, 200000) f[i + 1] = f[i] * (i + 1) % MOD; ll N, K, ans = 0; cin >> N >> K; // 1...10x...x01...1 if (K == 0) { cout << 1 << endl; return 0; } if (K == 1) { // 01even X = 0, Y = 1 // 01odd X = 1, Y = 1 if (N % 2) { cout << N - 2 << endl; } else { cout << 2 << endl; } return 0; } for (ll i = 0; i <= N - K; i += 2) { ans = (ans + C(N - i - 2, K - 2) * (i + 1)) % MOD; } cout << ans << endl; }