#include using namespace std; #include using namespace atcoder; using mint = modint998244353; //using mint = modint1000000007; using ll = long long; using ld = long double; using pll = pair; using tlll = tuple; constexpr ll INF = 1LL << 60; template bool chmin(T& a, T b) {if (a > b) {a = b; return true;} return false;} template bool chmax(T& a, T b) {if (a < b) {a = b; return true;} return false;} ll safemod(ll A, ll M) {return (A % M + M) % M;} ll divfloor(ll A, ll B) {if (B < 0) {return divfloor(-A, -B);} return (A - safemod(A, B)) / B;} ll divceil(ll A, ll B) {if (B < 0) {return divceil(-A, -B);} return divfloor(A + B - 1, B);} template void unique(vector &V) {V.erase(unique(V.begin(), V.end()), V.end());} template void sortunique(vector &V) {sort(V.begin(), V.end()); V.erase(unique(V.begin(), V.end()), V.end());} #define FINALANS(A) do {cout << (A) << '\n'; exit(0);} while (false) int main() { ll H, W, M; cin >> H >> W >> M; mint ans = 0; for (ll m = 1; m <= M; m++) { mint a = mint(M - m + 1).pow(H) - mint(M - m).pow(H); mint b = mint(M - m + 1).pow(W) - mint(M - m).pow(W); mint tmp = a * b; ans += tmp; //cerr << a.val() << " " << b.val() << endl; } cout << ans.val() << endl; }