#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using Vi = vector<int>;
using VVi = vector<Vi>;
using Vl = vector<ll>;
using VVl = vector<Vl>;
void tprsort(VVi& gr, Vi& tpr, Vi& par, int s) {
    for (auto v : gr[s]) {
        if (v == par[s]) {
            continue;
        }
        par[v] = s;
        tprsort(gr, tpr, par, v);
    }
    tpr.push_back(s);
}
int main () {
    ll m = 1e9 + 7;
    ll f2 = (m + 1) / 2;
    int N;
    cin >> N;
    VVi tree(N);
    VVl dist(N);
    for (int i = 1; i < N; i ++) {
        int a, b;
        ll c;
        cin >> a >> b >> c;
        a --;
        b --;
        tree[a].push_back(b);
        tree[b].push_back(a);
        dist[a].push_back(c);
        dist[b].push_back(c);
    }
    Vi tpr, par(N, -1);
    tprsort(tree, tpr, par, 0);
    ll ans = 0;
    for (int i_ = 0; i_ < 30; i_ ++) {
        Vl dp(N);
        ll kj = 0;
        for (auto u : tpr) {
            dp[u] = 1;
            ll sqsum = 1;
            for (int i = 0; i < tree[u].size(); i ++) {
                int v = tree[u][i];
                ll c = dist[u][i];
                if (v == par[u]) {
                    continue;
                }
                if ((c >> i_) & 1) {
                    dp[u] += dp[v];
                    sqsum += (dp[v] * dp[v]) % m;
                    sqsum %= m;
                }
            }
            kj += ((((dp[u] * dp[u]) % m - sqsum + m) % m) * f2) % m;
            kj %= m;
        }
        ans += (kj * ((1 << i_) % m)) % m;
        ans %= m;
    }
    cout << ans << endl;
}