#include using namespace std; #include using namespace atcoder; //using mint = modint998244353; using mint = modint1000000007; using ll = long long; using ld = long double; using pll = pair; using tlll = tuple; constexpr ll INF = 1LL << 60; template bool chmin(T& a, T b) {if (a > b) {a = b; return true;} return false;} template bool chmax(T& a, T b) {if (a < b) {a = b; return true;} return false;} ll safemod(ll A, ll M) {return (A % M + M) % M;} ll divfloor(ll A, ll B) {if (B < 0) {return divfloor(-A, -B);} return (A - safemod(A, B)) / B;} ll divceil(ll A, ll B) {if (B < 0) {return divceil(-A, -B);} return divfloor(A + B - 1, B);} template void unique(vector &V) {V.erase(unique(V.begin(), V.end()), V.end());} template void sortunique(vector &V) {sort(V.begin(), V.end()); V.erase(unique(V.begin(), V.end()), V.end());} #define FINALANS(A) do {cout << (A) << '\n'; exit(0);} while (false) template void printvec(vector &V) {int _n = V.size(); for (int i = 0; i < _n; i++) cout << V[i] << (i == _n - 1 ? "" : " ");cout << '\n';} template void printvect(vector &V) {for (auto v : V) cout << v << '\n';} template void printvec2(vector> &V) {for (auto &v : V) printvec(v);} int main() { ll N; cin >> N; vector A(N), B(N); for (ll i = 0; i < N; i++) { cin >> A.at(i); } for (ll i = 0; i < N; i++) { cin >> B.at(i); } vector S(N); S.at(0) = B.at(0); for (ll i = 0; i < N - 1; i++) { S.at(i + 1) = S.at(i) ^ B.at(i + 1); } //printvec(S); const ll K = 32; vector cnt(K, 0); ll cnt0 = 1, cnt1 = 0; ll lasts = 0; deque deq; ll ans = 0; for (ll i = 0; i < N; i++) { deq.push_back(i); for (ll k = 0; k < K; k++) { if (A.at(i) & (1LL << k)) cnt.at(k)++; } while (*max_element(cnt.begin(), cnt.end()) >= 2) { if (lasts == 0) cnt0--; else cnt1--; ll j = deq.front(); deq.pop_front(); for (ll k = 0; k < K; k++) { if (A.at(j) & (1LL << k)) cnt.at(k)--; } lasts = S.at(j); } ll tmp = (S.at(i) == 0 ? cnt0 : cnt1); ans += tmp; //cerr << i << " " << deq.size() << " " << cnt0 << " " << cnt1 << " " << tmp << endl; if (S.at(i) == 0) cnt0++; else cnt1++; } cout << ans << endl; }