#include using namespace std; #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<> #define rev(x) reverse(x); using ll=long long; using vl=vector; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[9]={0,-1,0,1,1,1,-1,-1,0}; const ll dx[9]={-1,0,1,0,1,-1,1,-1,0}; template inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; } struct Edge{ ll to,cost; }; template struct Dijkstra{ vector dist; vector prev; Dijkstra(vector> &g,int s){ dist=vector(g.size(),numeric_limits::max()/5); prev=vector(g.size(),-1); using pi=pair; priority_queue,greater> que; dist[s]=0; que.emplace(dist[s],s); while(!que.empty()){ T cost;int idx; tie(cost,idx)=que.top();que.pop(); if(dist[idx] get_path(int t){//到達できない場合、return=t; vector path; for (int cur = t; cur != -1; cur = prev[cur]) { path.push_back(cur); } reverse(path.begin(), path.end()); return path; } }; int main(){ ll n;cin >> n; vector> g(n); rep(i,n-1)g[i+1].push_back({i,0LL}); rep(i,n-1){ ll a;cin >> a;a--; g[i].push_back({a,1LL}); } Dijkstra dk(g,0); cout << dk.dist[n-1] << endl; }