#include <bits/stdc++.h>
using namespace std;

using ll = long long;
using VI = vector<int>;
using P = pair<int, int>;

#define REP(i, n) for (int i = 0; i < (int)(n); i++)
#define FOR(i, a, b) for (ll i = a; i < (ll)(b); i++)
#define ALL(a) (a).begin(),(a).end()

constexpr int INF = 1001001001;
constexpr ll LINF = 1001001001001001001ll;
constexpr int DX[] = {1, 0, -1, 0};
constexpr int DY[] = {0, 1, 0, -1};

template< typename T1, typename T2>
inline bool chmax(T1 &a, T2 b) {return a < b && (a = b, true); }
template< typename T1, typename T2>
inline bool chmin(T1 &a, T2 b) {return a > b && (a = b, true); }

const ll MOD = 1000000007;

int main() {
    int N;
    cin >> N;
    vector<vector<ll>> dp(N + 1, vector<ll>(N + 3, 0));
    // dp[i][j]条件を満たすi点グラフで最小の連結成分の大きさがj以上の場合
    REP(i, N + 2) dp[0][i] = 1;
    FOR(i, 3, N + 1) {
        dp[i][i] = 1;
        for (int j = i - 1; j >= 3; j--) {
            dp[i][j] = (dp[i][j + 1] + dp[i - j][j]) % MOD;
        }
    }
    cout << dp[N][3] << endl;
}