#include <bits/stdc++.h>
using namespace std;
#define int long long
constexpr int inf = 1e18;
constexpr int maxn = 2e5 + 5;
constexpr int mod = 998244353;

constexpr int P = 1000000007;
// assume -P <= x < 2P
int norm(int x) 
{
  if (x < 0) x += P;
  if (x >= P) x -= P;
  return x;
}
template<class T>
T qpow(T a, int b) 
{
  T res = 1;
  for (; b; b /= 2, a *= a) 
  {
    if (b % 2) res *= a;
  }
  return res;
}
struct Z
{
  int x;
  Z(int x = 0) : x(norm(x)){}
  int val()const{return x;}
  Z operator - ()const{return Z(norm(P - x));}
  Z inv()const {assert(x != 0); return qpow(*this, P - 2);}
  Z &operator *= (const Z &rhs){x = x * rhs.x % P; return *this;}
  Z &operator += (const Z &rhs){x = norm(x + rhs.x); return *this;}
  Z &operator -= (const Z &rhs){x = norm(x - rhs.x); return *this;}
  Z &operator /= (const Z &rhs){return *this *= rhs.inv();}
  friend Z operator * (const Z &lhs, const Z &rhs){Z ret = lhs; ret *= rhs; return ret;}
  friend Z operator + (const Z &lhs, const Z &rhs){Z ret = lhs; ret += rhs; return ret;}
  friend Z operator - (const Z &lhs, const Z &rhs){Z ret = lhs; ret -= rhs; return ret;}
  friend Z operator / (const Z &lhs, const Z &rhs){Z ret = lhs; ret /= rhs; return ret;}
};

inline void solve()
{
  int n; cin >> n;

  vector f(n + 1, vector<Z>(n + 1));
  f[0][0] = 1;
  for(int i = 1; i <= n; i ++)
  {
    for (int j = 0; j <= n; j ++)
    {
      f[i][j] = f[i - 1][j];
      if (j >= i && i >= 3)
      {
        f[i][j] += f[i][j - i];
      }
    }
  }
  cout << f[n][n].val() << "\n";
}

signed main()
{
  ios::sync_with_stdio(false);
  cin.tie(nullptr);
  solve();
  return 0;
}
/*
The details you should care:

*/