#include #include #include #define rep(i, l, n) for (int i = (l); i < (n); i++) using namespace std; using ll = long long; template using V = vector; int main(void) { ll n, m; cin >> n >> m; ll ans = 0; V > naname1(2, set({})); V > naname2(2, set({})); rep(i, 0, m) { ll x, y; cin >> x >> y; x--; y--; ll p = x - y, q = x + y; int b = q & 1; if (naname1[b].find(p) == naname1[b].end()) { ans += min(n - 1 + p, n - 1) - max(p, (ll)0) + 1; auto itr1 = naname2[b].lower_bound(max(p, -p)); auto itr2 = naname2[b].upper_bound(min(2 * (n - 1) - p, 2 * (n - 1) + p)); ans -= distance(itr1, itr2); naname1[b].insert(p); } if (naname2[b].find(q) == naname2[b].end()) { ans += min(q, n - 1) - max(-n + 1 + q, (ll)0) + 1; auto itr1 = naname1[b].lower_bound(max(-q, q - 2 * (n - 1))); auto itr2 = naname1[b].upper_bound(min(2 * (n - 1) - q, q)); ans -= distance(itr1, itr2); naname2[b].insert(q); } } cout << ans << endl; return 0; }