#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define FORR2(x,y,arr) for(auto& [x,y]:arr)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
template<class T> bool chmax(T &a, const T &b) { if(a<b){a=b;return 1;}return 0;}
template<class T> bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;}
//-------------------------------------------------------


int N;
int A[3030],B[3030];

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N;
	int ma=0;
	FOR(i,N) {
		cin>>A[i];
		ma=max(ma,A[i]);
	}
	FOR(i,N) {
		cin>>B[i];
		ma=max(ma,B[i]);
	}
	
	x=1;
	while(x*2<=ma) x*=2;
	vector<vector<int>> ret;
	FOR(i,N) if(B[i]&x) {
		if((A[0]&x)==0) {
			ret.push_back({1,0,i});
			A[0]^=B[i];
			break;
		}
	}
	
	FOR(i,N) if(A[i]&x) {
		FOR(j,N) {
			if((B[j]&x)==0) {
				ret.push_back({2,i,j});
				B[j]^=A[i];
			}
		}
		FOR(i,N) if(A[i]&x) {
			ret.push_back({1,i,0});
			A[i]^=B[0];
		}
		break;
	}
	cout<<ret.size()<<endl;
	FORR(a,ret) cout<<a[0]<<" "<<a[1]+1<<" "<<a[2]+1<<endl;
	
	
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}