#include #include #define rep(i,n) for(int i = 0; i < (int)(n); i++) using namespace std; using namespace atcoder; using LL = long long; using P = pair; using vv = vector>; const int INF = (int)1e9; const LL LINF = (LL)1e18; pair, vector> Eratosthenes(const int N){ vector divisor(N + 1); vector res; for(int i = 2; i <= N; i++){ if(divisor[i] == 0){ divisor[i] = 1; res.emplace_back(i); for(int j = 2 * i; j <= N; j += i) divisor[j] = i; } } return pair, vector>(res, divisor); } int main(){ int N; cin >> N; vv A(N, vector(2)); rep(i,N) cin >> A[i][0] >> A[i][1]; pair,vector> E = Eratosthenes(1000005); map primes; for(auto p : E.first) primes[p]++; two_sat ts(N); rep(i,N){ rep(j,N){ if(i == j){ rep(u,2){ string s = to_string(A[i][u]) + to_string(A[j][u^1]); int a = stoi(s); if(primes[a]) ts.add_clause(i, u, j, u); } } else{ rep(u,2){ rep(v,2){ string s1 = to_string(A[i][u]) + to_string(A[j][v^1]); string s2 = to_string(A[j][v]) + to_string(A[i][u^1]); int a = stoi(s1), b = stoi(s2); if(primes[a] or primes[b]) ts.add_clause(i, u, j, v); } } } } } bool ans = ts.satisfiable(); if(ans) cout << "Yes" << endl; else cout << "No" << endl; return 0; }