#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define FORR2(x,y,arr) for(auto& [x,y]:arr)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
template<class T> bool chmax(T &a, const T &b) { if(a<b){a=b;return 1;}return 0;}
template<class T> bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;}
//-------------------------------------------------------


int N;
int C[1010101];

ll mi[101010];
ll base[101010];
vector<int> cand[101010];

template<int um> class UF {
	public:
	vector<int> par,rank,cnt;
	UF() {par=rank=vector<int>(um,0); cnt=vector<int>(um,1); for(int i=0;i<um;i++) par[i]=i;}
	void reinit(int num=um) {int i; FOR(i,num) rank[i]=0,cnt[i]=1,par[i]=i;}
	int operator[](int x) {return (par[x]==x)?(x):(par[x] = operator[](par[x]));}
	int count(int x) { return cnt[operator[](x)];}
	int operator()(int x,int y) {
		if((x=operator[](x))==(y=operator[](y))) return x;
		cnt[y]=cnt[x]=cnt[x]+cnt[y];
		if(rank[x]>rank[y]) return par[x]=y;
		rank[x]+=rank[x]==rank[y]; return par[y]=x;
	}
};
UF<101010> uf;

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N;
	ll ret=0;
	FOR(i,N) {
		cin>>x;
		if(C[x]) ret+=x;
		else C[x]=1;
	}
	
	for(i=1;i<=100000;i++) {
		for(j=i;j<=100000;j+=i) if(C[j]) cand[i].push_back(j);
	}
	
	priority_queue<pair<ll,int>> Q;
	for(i=1;i<=100000;i++) if(cand[i].size()>1) {
		reverse(ALL(cand[i]));
		base[i]=cand[i].back();
		cand[i].pop_back();
		Q.push({-cand[i].back()*base[i]/i,i});
	}
	
	while(Q.size()) {
		ll co=-Q.top().first;
		i=Q.top().second;
		Q.pop();
		if(uf[base[i]]!=uf[cand[i].back()]) {
			ret+=co;
			uf(base[i],cand[i].back());
		}
		cand[i].pop_back();
		if(cand[i].size()) {
			Q.push({-cand[i].back()*base[i]/i,i});
		}
	}
	
	
	cout<<ret<<endl;
	
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}