#include #include typedef long long int ll; typedef long long int ull; #define MP make_pair using namespace std; using namespace atcoder; typedef pair P; // const ll MOD = 998244353; const ll MOD = 1000000007; // using mint = modint998244353; using mint = modint1000000007; const double pi = 3.1415926536; const int MAX = 2000005; long long fac[MAX], finv[MAX], inv[MAX]; template using min_priority_queue = priority_queue, greater>; void COMinit() { fac[0] = fac[1] = 1; finv[0] = finv[1] = 1; inv[1] = 1; for (int i = 2; i < MAX; i++){ fac[i] = fac[i - 1] * i % MOD; inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD; finv[i] = finv[i - 1] * inv[i] % MOD; } } // 二項係数計算 long long COM(int n, int k){ if (n < k) return 0; if (n < 0 || k < 0) return 0; return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD; } ll gcd(ll x, ll y) { if (y == 0) return x; else if (y > x) { return gcd (y, x); } else return gcd(x % y, y); } ll lcm(ll x, ll y) { return x / gcd(x, y) * y; } ll my_sqrt(ll x) { ll m = 0; ll M = 3000000001; while (M - m > 1) { ll now = (M + m) / 2; if (now * now <= x) { m = now; } else { M = now; } } return m; } ll keta(ll n) { ll ret = 0; while (n) { n /= 10; ret++; } return ret; } ll ceil(ll n, ll m) { // n > 0, m > 0 ll ret = n / m; if (n % m) ret++; return ret; } ll pow_ll(ll x, ll n) { if (n == 0) return 1; if (n % 2) { return pow_ll(x, n - 1) * x; } else { ll tmp = pow_ll(x, n / 2); return tmp * tmp; } } vector compress(vector v) { // [3 5 5 6 1 1 10 1] -> [1 2 2 3 0 0 4 0] vector u = v; sort(u.begin(), u.end()); u.erase(unique(u.begin(),u.end()),u.end()); map mp; for (int i = 0; i < u.size(); i++) { mp[u[i]] = i; } for (int i = 0; i < v.size(); i++) { v[i] = mp[v[i]]; } return v; } int main() { ll n, m; cin >> n >> m; ll a[n + 1]; for (int i = 2; i <= n; i++) cin >> a[i]; mint kaijou[200001]; kaijou[0] = 1; mint ans = 0; for (int i = 1; i <= 200000; i++) kaijou[i] = kaijou[i - 1] * i; mint now = 1; ll A = n - 1; ll B = m - 1; for (ll i = 1; i <= A; i++) { now *= B + i; now *= pow_mod(i, MOD - 2, MOD); } for (ll i = 2; i <= n; i++) { // ll a = n + 1 - i; // ll b = m - 1; // ans += a[i] * COM(a + b, a); // cout << n + 1 - i << ' ' << m - 1 << ' ' << now.val() << endl; ans += now * a[i]; now *= n + 1 - i; now *= pow_mod(n + 1 - i + m - 1, MOD - 2, MOD); } cout << ans.val() << endl; return 0; }