#pragma GCC optimize ("Ofast")
#pragma GCC optimize ("unroll-loops")
#pragma GCC target ("avx")

#include <cassert>
#include <cmath>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <bitset>
#include <complex>
#include <deque>
#include <functional>
#include <iostream>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <sstream>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

using namespace std;

using Int = long long;

template <class T1, class T2> ostream &operator<<(ostream &os, const pair<T1, T2> &a) { return os << "(" << a.first << ", " << a.second << ")"; };
template <class T> void pv(T a, T b) { for (T i = a; i != b; ++i) cerr << *i << " "; cerr << endl; }
template <class T> bool chmin(T &t, const T &f) { if (t > f) { t = f; return true; } return false; }
template <class T> bool chmax(T &t, const T &f) { if (t < f) { t = f; return true; } return false; }


unsigned M;
void Add(unsigned &t, unsigned f) {
  t += f;
  t = (t >= M) ? (t - M) : t;
}
void Sub(unsigned &t, unsigned f) {
  t -= f;
  t = (t >= M) ? (t + M) : t;
}

int N, K;
int A[110];

int L;
int S, T;

unsigned dp[47][50'010];
unsigned ans0[50'010];
unsigned ans1[50'010];

int main() {
  for (; ~scanf("%d%u%d", &N, &M, &K); ) {
    for (int i = 0; i < N; ++i) {
      scanf("%d", &A[i]);
    }
    sort(A, A + N);
    
    L = ((N + 1) + 1) / 2;
    assert(N < 2 * L);
    S = 0;
    for (int i = 0; i < N; ++i) {
      S += A[i];
    }
    T = S / 2;
    
    M *= 2;
    
    // +
    memset(dp, 0, sizeof(dp));
    dp[0][0] = 1 % M;
    for (int i = 0; i < N; ++i) {
      for (int k = L; --k >= 0; ) if (i >= k) {
        for (int x = 0; x + A[i] <= T; ++x) {
          Add(dp[k + 1][x + A[i]], dp[k][x]);
        }
      }
      if (i + 1 >= L) {
        for (int x = 0; x <= T; ++x) {
          Add(dp[0][x], dp[L][x]);
        }
        memset(dp[L], 0, (T + 1) * sizeof(dp[0][0]));
      }
    }
    memcpy(ans0, dp[K % L], (T + 1) * sizeof(dp[0][0]));
    memcpy(ans1, dp[(N - K) % L], (T + 1) * sizeof(dp[0][0]));
    
    // -
#ifdef LOCAL
    memset(dp, 0, sizeof(dp));
#endif
    dp[0][0] = 1 % M;
    for (int i = 0; i < N; ++i) {
      for (int k = L; --k >= 0; ) if (i >= k) {
        for (int x = 0; x + A[i] <= T; ++x) {
          Add(dp[k + 1][x + A[i]], dp[k][x]);
        }
      }
      if (i + 1 >= L) {
        for (int x = 0; x <= T; ++x) {
          Sub(dp[0][x], dp[L][x]);
        }
        memset(dp[L], 0, (T + 1) * sizeof(dp[0][0]));
      }
    }
    for (int x = 0; x <= T; ++x) {
      unsigned a = ans0[x];
      (K >= L) ? Sub(a, dp[K - L][x]) : Add(a, dp[K][x]);
      assert(a % 2 == 0);
      ans0[x] = a / 2;
    }
    for (int x = 0; x <= T; ++x) {
      unsigned a = ans1[x];
      (N - K >= L) ? Sub(a, dp[(N - K) - L][x]) : Add(a, dp[N - K][x]);
      assert(a % 2 == 0);
      ans1[x] = a / 2;
    }
    
    for (int x = 1; x <= S; ++x) {
      if (x > 1) printf(" ");
      printf("%u", (x <= T) ? ans0[x] : ans1[S - x]);
    }
    puts("");
  }
  return 0;
}