//Let's join Kaede Takagaki Fan Club !! #pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; #define int long long //#define L __int128 typedef long long ll; typedef pair P; typedef pair P1; typedef pair P2; #define pu push #define pb push_back #define eb emplace_back #define mp make_pair #define eps 1e-7 #define INF 1000000000 #define a first #define b second #define fi first #define sc second //#define rng(i,a,b) for(int i=(int)(a);i<(int)(b);i++) #define rep(i,x) for(int i=0;i bool chmax(t&a,u b){if(a bool chmin(t&a,u b){if(b using vc=vector; template ostream& operator<<(ostream& os,const pair& p){ return os<<"{"< ostream& operator<<(ostream& os,const vc& v){ os<<"{"; for(auto e:v)os<> 30)) * 0xbf58476d1ce4e5b9; x = (x ^ (x >> 27)) * 0x94d049bb133111eb; return x ^ (x >> 31); } size_t operator()(uint64_t x) const { static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count(); return splitmix64(x + FIXED_RANDOM); } //don't make x negative! size_t operator()(pair x)const{ return operator()(uint64_t(x.first)<<32|x.second); } }; //unordered_set -> dtype, null_type //unordered_map -> dtype(key), dtype(value) using namespace __gnu_pbds; template using hash_table=gp_hash_table; template void g(T &a){ cin >> a; } template void o(const T &a,bool space=false){ cout << a << (space?' ':'\n'); } //ios::sync_with_stdio(false); const ll mod = 998244353; //const ll mod = 1000000007; mt19937_64 mt(chrono::steady_clock::now().time_since_epoch().count()); template void add(T&a,T b){ a+=b; if(a >= mod) a-=mod; } ll modpow(ll x,ll n){ ll res=1; while(n>0){ if(n&1) res=res*x%mod; x=x*x%mod; n>>=1; } return res; } #define _sz 1 ll F[_sz],R[_sz]; void make(){ F[0] = 1; for(int i=1;i<_sz;i++) F[i] = F[i-1]*i%mod; R[_sz-1] = modpow(F[_sz-1], mod-2); for(int i=_sz-2;i>=0;i--) R[i] = R[i+1] * (i+1) % mod; } ll C(int a,int b){ if(b < 0 || a < b) return 0; return F[a]*R[b]%mod*R[a-b]%mod; } //o(ans?"Yes":"No"); int dp[105][105][105], n, cnt[105]; int dp2[2][105][105][105]; void solve(){ cin >> n; repn(i, n){ int v; cin >> v; cnt[v] ++; } int ans = 0; if(cnt[0] == 0 and cnt[1] == 0) ans = 1; { dp[102][0][0] = 1; { for(int i=102;i>=3;i--){ for(int g=0;g<=100;g++){ for(int need=0;need*i<=n;need++){ if(dp[i][g][need] == 0) continue; int zan = cnt[i-1]; for(int m=0;;m++){ if(m <= zan){ int rem = zan-m; if(rem >= need){ int ng = g + rem-need; int nxt = need; add(dp[i-1][ng][nxt], dp[i][g][need]); } else{ int ng = g; int nxt = need + (need-rem); if(nxt*(i-1) > n) break; else add(dp[i-1][ng][nxt], dp[i][g][need]); } } else{ int ng = g; int nxt = need + need + m - zan; if(nxt*(i-1) > n) break; else add(dp[i-1][ng][nxt], dp[i][g][need]); } } } } } } rep(g, 105) rep(c, 105){ //dp[0][2][g][c] if(dp[2][g][c] == 0) continue; int zan = g + cnt[0] + cnt[1]; zan -= c*2; if(zan < 0) continue; int p = (zan+1)*(zan+2)/2-1; add(ans, dp[2][g][c]*p%mod); } } { dp2[0][102][0][0] = 1; rep(s, 2){ for(int i=102;i>=3;i--){ for(int g=0;g<=100;g++){ for(int need=0;need*i<=n;need++){ if(dp2[s][i][g][need] == 0) continue; int zan = cnt[i-1]; for(int m=0;;m++){ if(s and m) break; if(m <= zan){ int rem = zan-m; if(rem >= need){ int ng = g + rem-need; int nxt = need; add(dp2[s][i-1][ng][nxt], dp2[s][i][g][need]); } else{ int ng = g; int nxt = need + (need-rem); if(nxt*(i-1) > n) break; else add(dp2[s][i-1][ng][nxt], dp2[s][i][g][need]); } } else{ int ng = g; int nxt = need + need + m - zan; if(nxt*(i-1) > n) break; else add(dp2[s][i-1][ng][nxt], dp2[s][i][g][need]); } if(s == 0 and need == 0 and m and m <= cnt[i-1]){ int ng = g + cnt[i-1] - m + 1; int nxt = 1; add(dp2[1][i-1][ng][nxt], dp2[s][i][g][need]); } } } } } } rep(g, 105) rep(c, 105){ //dp[0][2][g][c] if(dp2[0][2][g][c] == 0 or c == 0) continue; int zan = g + cnt[0] + cnt[1]; zan -= c*2; if(zan < 0) continue; add(ans, dp2[0][2][g][c]); } rep(g, 105) rep(c, 105){ //dp[1][2][g][c] if(dp2[1][2][g][c] == 0) continue; int zan = g + cnt[0] + cnt[1]; zan -= c*2; if(zan < 0) continue; add(ans, dp2[1][2][g][c]); } } o(ans); } signed main(){ cin.tie(0); ios::sync_with_stdio(0); cout<> t; while(t--) solve(); }