#include #include #define rep(i,b) for(int i=0;i=0;i--) #define rep1(i,b) for(int i=1;i using mpq = priority_queue, greater>; template bool chmax(T &a, const T &b) { if (a bool chmin(T &a, const T &b) { if (b ll sumv(const vector&a){ll res(0);for(auto&&x:a)res+=x;return res;} bool yn(bool a) { if(a) {cout << "Yes" << endl; return 1;} else {cout << "No" << endl; return 0;}} #define dame { cout << "No" << endl; return 0;} #define dame1 { cout << -1 << endl; return 0;} #define test(x) cout << "test" << x << endl; #define deb(x,y) cout << x << " " << y << endl; #define deb3(x,y,z) cout << x << " " << y << " " << z << endl; #define deb4(x,y,z,x2) cout << x << " " << y << " " << z << " " << x2 << endl; #define out cout << ans << endl; #define outv fore(yans , ans) cout << yans << "\n"; #define show(x) cerr<<#x<<" = "<; using pil = pair; using pli = pair; using pii = pair; using tp = tuple; using vi = vector; using vl = vector; using vs = vector; using vb = vector; using vpii = vector; using vpli = vector; using vpll = vector; using vpil = vector; using vvi = vector>; using vvl = vector>; using vvs = vector>; using vvb = vector>; using vvpii = vector>; using vvpli = vector>; using vvpll = vector; using vvpil = vector; using mint = modint998244353; using vm = vector; using vvm = vector>; vector dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1}; ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;} ll lcm(ll a, ll b) { return a/gcd(a,b)*b;} const double eps = 1e-10; const ll LINF = 1001002003004005006ll; const int INF = 1001001001; int main(){ int n; cin>>n; vl x(n),a(n); unordered_map mp; vvi e(n); rep(i,n) {cin>>x[i]; mp[x[i]] = i;} rep(i,n){ cin>>a[i]; if (mp.count(x[i] - a[i])){ e[mp[x[i]-a[i]]].pb(i); } if (mp.count(x[i] + a[i])){ e[mp[x[i]+a[i]]].pb(i); } } vl ans(n); auto dfs = [&](auto dfs ,int root, int x , int pre) -> void{ fore(y , e[x]){ if (y == pre) continue; if (ans[y]) continue; ans[y] = ans[root]; dfs(dfs , root , y , x); } }; vpll v(n); rep(i,n) v[i] = {x[i] + a[i] , i}; sort(rrng(v)); rep(i,n){ int k = v[i].se; if (ans[k]) continue; ans[k] = v[i].fi; dfs(dfs , k , k , -1); } rep(i,n) ans[i] -= x[i]; outv; return 0; }