#include <bits/stdc++.h>
//#include <atcoder/all>
//using namespace atcoder;
using namespace std;
using ll = long long;
using vll = vector<ll>;
using vvll = vector<vll>;
using vvvll = vector<vvll>;
using vb = vector<bool>;
using vvb = vector<vb>;
using vvvb = vector<vvb>;
#define all(A) A.begin(),A.end()
#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)
using pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;

template<class T>
bool chmax(T& p, T q) {
    if (p < q) {
        p = q;
        return 1;
    }
    else {
        return 0;
    }
}
template<class T>
bool chmin(T& p, T q) {
    if (p > q) {
        p = q;
        return 1;
    }
    else {
        return 0;
    }
}
ll gcd(ll(a), ll(b)) {
    ll c = a;
    while (a % b != 0) {
        c = a % b;
        a = b;
        b = c;
    }
    return b;
}
ll Eugrid(ll A, ll B, ll& x, ll& y) {
    if (B == 0) {
        x = 1;
        y = 0;
        return A;
    }
    ll C = gcd(A, B);
    ll D = Eugrid(B, A % B, y, x);
    y -= A / B * x;
    return D;
}//Ax+By=gcd(A,B)の解
vector<ll> fact, factinv, inv;
ll mod = 1e9 + 7;
void prenCkModp(ll n) {
	fact.resize(n + 5);
	factinv.resize(n + 5);
	inv.resize(n + 5);
	fact.at(0) = fact.at(1) = 1;
	factinv.at(0) = factinv.at(1) = 1;
	inv.at(1) = 1;
	for (ll i = 2; i < n + 5; i++) {
		fact.at(i) = (fact.at(i - 1) * i) % mod;
		inv.at(i) = mod - (inv.at(mod % i) * (mod / i)) % mod;
		factinv.at(i) = (factinv.at(i - 1) * inv.at(i)) % mod;
	}

}
ll nCk(ll n, ll k) {
	if (n < k) return 0;
	return fact.at(n) * (factinv.at(k) * factinv.at(n - k) % mod) % mod;
}
ll N,M;
vvll G;

vll DP;
vector<bool> seen;
ll dfs(ll X){
    if(seen[X])return DP[X];
    seen[X]=1;
    ll res=0;
    for(auto v:G[X]){
        chmax(res,dfs(v)+1);
    }
    DP[X]=res;
    return res;
}

int main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    
    ll T;
    cin>>T;
    rep(t,T){
        string S;
        cin>>S;
        ll N=S.size();
        vll D(N);
        rep(i,N)D[i]=S[i]-'0';
        rep(j,N-1){
            vll T(N-1-j);
            rep(i,N-1-j){
                T[i]=(D[i]+D[i+1]);
                if(T[i]>9)T[i]=T[i]/10+T[i]%10;
            }
            D=T;
        }
        cout<<D[0]<<endl;
    }
}