# import pypyjit
# pypyjit.set_param('max_unroll_recursion=-1')
import sys
from itertools import combinations, permutations, product, accumulate, groupby
from collections import defaultdict, deque, Counter
from functools import reduce
from operator import add, mul
import heapq
import bisect
import math
import copy

from sklearn.cluster import ward_tree
 
sys.setrecursionlimit(10 ** 9)
input = lambda: sys.stdin.readline().rstrip()
INF = float("inf")
MOD = 10 ** 9 + 7


class WarshallFloyd():
    def __init__(self, N):
        self.N = N
        self.d = [[float("inf") for i in range(N)]
                  for i in range(N)]  # d[u][v] : 辺uvのコスト(存在しないときはinf)

    def add(self, u, v, c, directed=False):
        """
        0-indexedであることに注意
        u = from, v = to, c = cost
        directed = Trueなら、有向グラフである
        """
        if directed is False:
            self.d[u][v] = min(c, self.d[u][v])
            self.d[v][u] = min(c, self.d[v][u])
        else:
            self.d[u][v] = min(c, self.d[u][v])

    def WarshallFloyd_search(self):
        # これを d[i][j]: iからjへの最短距離 にする
        # 本来無向グラフでのみ全域木を考えるが、二重辺なら有向でも行けそう
        # d[i][i] < 0 なら、グラフは負のサイクルを持つ
        for k in range(self.N):
            for i in range(self.N):
                for j in range(self.N):
                    self.d[i][j] = min(
                        self.d[i][j], self.d[i][k] + self.d[k][j])
        hasNegativeCycle = False
        for i in range(self.N):
            if self.d[i][i] < 0:
                hasNegativeCycle = True
                break
        for i in range(self.N):
            self.d[i][i] = 0
        return hasNegativeCycle, self.d

N, M = map(int ,input().split())
STD  = [list(map(int, input().split())) for i in range(M)]
graph = WarshallFloyd(N)
for s, t, d in STD:
    graph.add(s-1, t-1, d, True)

_, d = graph.WarshallFloyd_search()
for i in range(N):
    for j in range(N):
        if d[i][j] == INF:
            d[i][j] = 0
for i in range(N):
    print(sum(d[i]))