#include <bits/stdc++.h>
using namespace std;

#define rep(i,n) for(int i = 0; i < (int)n; i++)
#define FOR(n) for(int i = 0; i < (int)n; i++)
#define repi(i,a,b) for(int i = (int)a; i < (int)b; i++)
#define pb push_back
#define m0(x) memset(x,0,sizeof(x))
#define fill(x,y) memset(x,y,sizeof(x))
#define bg begin()
#define ed end()
#define all(x) x.bg,x.ed
//#define mp make_pair
#define vi vector<int>
#define vvi vector<vi>
#define vll vector<ll>
#define vvll vector<vll>
#define vs vector<string>
#define vvs vector<vs>
#define vc vector<char>
#define vvc vector<vc>
#define pii pair<int,int>
#define pllll pair<ll,ll>
#define vpii vector<pair<int,int>>
#define vpllll vector<pair<ll,ll>>
#define vpis vector<pair<int,string>>
#define vplls vector<pair<ll, string>>
#define vpsi vector<pair<string, int>>
#define vpsll vector<pair<string, ll>>

template<typename T>
void chmax(T &a, const T &b) {a = (a > b? a : b);}
template<typename T>
void chmin(T &a, const T &b) {a = (a < b? a : b);}

using ll = long long;
using ld = long double;
using ull = unsigned long long;

const ll INF = numeric_limits<long long>::max() / 2;
const ld pi = 3.1415926535897932384626433832795028;
const ll mod = 1e9 + 7;
int dx[] = {-1, 0, 1, 0, -1, -1, 1, 1};
int dy[] = {0, -1, 0, 1, -1, 1, -1, 1};

#define int long long

struct fenwick_tree {
    int n, sz;
    vector<int> dat;
    function<int(int, int)> f = [](int x, int y) {return (x + y) % mod;};

    fenwick_tree(int n_) : dat(4*n_, 0), sz(n_) {
        int x = 1;
        while(x < n_) x *= 2;
        n = x;
    }

    void add(int i, int x) {
        i += n - 1;
        dat[i] += x;
        while(i > 0) {
            i = (i - 1) / 2;
            dat[i] = f(dat[i * 2 + 1], dat[i * 2 + 2]);
        }
    }

    void insert(int i) {
        return add(i, 1);
    }

    void erase(int i) {
        return add(i, -1);
    }

    void update(int i, int x) {
        i += n - 1;
        dat[i] = x;
        while(i > 0) {
            i = (i - 1) / 2;
            dat[i] = f(dat[i * 2 + 1], dat[i * 2 + 2]);
        }
    }

    int get_sum(int a, int b) {
        return get_sum_sub(a, b, 0, 0, n);
    }
    int get_sum_sub(int a, int b, int k, int l, int r) {
        if(r <= a || b <= l) {
            return 0;
        }else if(a <= l && r <= b) {
            return dat[k];
        }else {
            int vl = get_sum_sub(a, b, k * 2 + 1, l, (l + r) / 2);
            int vr = get_sum_sub(a, b, k * 2 + 2, (l + r) / 2, r);
            return f(vl, vr);
        }
    }

    int get(int i) {
        return dat[i + n - 1];
    }

    inline void print() {
        cout << "{ ";
        for(int i = 0; i < sz; i++) {
            cout << dat[i + n - 1] << " ";
        }
        cout << "}\n";
    }
};

int two[200100];

void solve() {
    two[0] = 1;
    FOR(200099) two[i+1] = two[i]*2%mod;
    
    int n;
    cin >> n;
    vi a(n);
    FOR(n) cin >> a[i];

    vi val_a = a;
    sort(all(val_a));
    val_a.erase(unique(all(val_a)), val_a.end());

    for(auto& e : a) e = (int)(lower_bound(all(val_a), e) - val_a.begin());

    // for(auto e : a) cout << e << " "; cout << "\n";

    int ans = 0;

    fenwick_tree f(n+1);
    fenwick_tree b(n+1);
    FOR(n) b.add(a[i], two[n-1-i]);

    FOR(n) {
        b.add(a[i], -two[n-1-i]);

        ans += f.get_sum(0, a[i]) * b.get_sum(0, a[i]) % mod;
        ans += f.get_sum(a[i]+1, n+1) * b.get_sum(a[i]+1, n+1) % mod;
        ans %= mod;

        f.add(a[i], two[i]);
    }

    cout << ans << endl;
}

signed main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    solve();
    return 0;
}