#include #include #define rep(i,b) for(int i=0;i=0;i--) #define rep1(i,b) for(int i=1;i using mpq = priority_queue, greater>; template bool chmax(T &a, const T &b) { if (a bool chmin(T &a, const T &b) { if (b ll sumv(const vector&a){ll res(0);for(auto&&x:a)res+=x;return res;} bool yn(bool a) { if(a) {cout << "Yes" << endl; return 1;} else {cout << "No" << endl; return 0;}} #define dame { cout << "No" << endl; return 0;} #define dame1 { cout << -1 << endl; return 0;} #define test(x) cout << "test" << x << endl; #define deb(x,y) cout << x << " " << y << endl; #define deb3(x,y,z) cout << x << " " << y << " " << z << endl; #define deb4(x,y,z,x2) cout << x << " " << y << " " << z << " " << x2 << endl; #define out cout << ans << endl; #define outv fore(yans , ans) cout << yans << "\n"; #define show(x) cerr<<#x<<" = "<; using pil = pair; using pli = pair; using pii = pair; using tp = tuple; using vi = vector; using vl = vector; using vs = vector; using vb = vector; using vpii = vector; using vpli = vector; using vpll = vector; using vpil = vector; using vvi = vector>; using vvl = vector>; using vvs = vector>; using vvb = vector>; using vvpii = vector>; using vvpli = vector>; using vvpll = vector; using vvpil = vector; using mint = modint998244353; using vm = vector; using vvm = vector>; vector dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1}; ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;} ll lcm(ll a, ll b) { return a/gcd(a,b)*b;} const double eps = 1e-10; const ll LINF = 1001002003004005006ll; const int INF = 1001001001; int main(){ int n,m; cin>>n>>m; vl v(n); rep(i,n) cin>>v[i]; int l = 1 << m; vvl sum(l , vl(m+1)); rep(i,n){ string s; cin>>s; ll tmp = 0; rep(j,m) if (s[j] == 'o') tmp += (1 << j); sum[tmp][0] += v[i]; } rep1(i,m+1){ rep(j,l){ sum[j][i] += sum[j][i-1]; if ((j >> (i-1) & 1) == 1){ int nj = j - (1 << (i-1)); sum[j][i] += sum[nj][i-1]; } } } vvi st(m+1); rep(i,l){ int cnt = 0; rep(j,m) if ((i >> j & 1) == 1) cnt++; st[cnt].pb(i); } int nj = l-1 - 0; vl dp(l); dp[0] = 0; rep1(i,m+1){ fore(y , st[i]){ int yj = l - 1 - y; ll sumy = sum[yj][m]; rep(k , m){ if ((y >> k & 1) == 1){ int ny = y - (1 << k); int nyj = l - 1 - ny; ll sumny = sum[nyj][m]; ll diff = sumny - sumy; chmax(dp[y] , dp[ny] + diff * diff); } } } } cout << dp[l-1] << endl; return 0; }