#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; typedef long long ll; const ll mod = 1000000007; const ll INF = (ll)1000000007 * 1000000007; typedef pair P; #define rep(i, n) for (int i = 0; i < n; i++) #define per(i, n) for (int i = n - 1; i >= 0; i--) #define Rep(i, sta, n) for (int i = sta; i < n; i++) #define Per(i, sta, n) for (int i = n - 1; i >= sta; i--) typedef long double ld; const ld eps = 1e-8; const ld pi = acos(-1.0); typedef pair LP; int dx[8] = {1, -1, 0, 0, 1, 1, -1, -1}; int dy[8] = {0, 0, 1, -1, 1, -1, 1, -1}; template using max_heap = priority_queue; template using min_heap = priority_queue, greater<>>; template bool chmax(T &a, const T &b) { if (a < b) { a = b; return 1; } return 0; } template bool chmin(T &a, const T &b) { if (b < a) { a = b; return 1; } return 0; } int n; ll m, a[200010]; map ma; void solve() { cin >> n >> m; rep(i, n) { cin >> a[i]; ma[a[i] % m]++; ma[m - a[i] % m] += 0; } int ans = 0; for (auto p : ma) { if (p.first < (m + 1) / 2 && p.first > 0) { // cout << p.first << " " << p.second << endl; // cout << m - p.first << " " << ma[m - p.first] << endl; ans += max(p.second, ma[m - p.first]); } else if (p.first == m / 2 || p.first == 0) if (p.second >= 1) ans++; } cout << ans << endl; } int main() { ios::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(50); solve(); }