#include #define int ll #define rep(i, N) for(int i = 0; i < (int)(N); ++i) #define rep1(i, N) for(int i = 1; i <= (int)(N); ++i) #define per(i, N) for(int i = (N)-1; i >= 0; --i) #define all(v) (v).begin(), (v).end() #define rall(v) (v).rbegin(), (v).rend() #define bit(n, k) ((n) >> (k)) #define pcnt(n) (__builtin_popcount(n)) #define TakAo(ans) ans ? cout << "Takahashi\n" : cout << "Aoki\n" #define YesNo(ans) ans ? cout << "Yes\n" : cout << "No\n" #define endl '\n' #define fi first #define se second #define mkpr make_pair #define mktpl make_tuple #define eb emplace_back using namespace std; using ll = int64_t; using ull = uint64_t; using ld = long double; using point = struct{ ll x, y; }; using pointld = struct{ ld x, y; }; template using max_heap = priority_queue; template using min_heap = priority_queue, greater>; template using vec = vector; template using vvec = vec>; template using vvvec = vec>; template using vvvvec = vvec>; constexpr ld EPS = 1e-10; constexpr int INF = 1001001001; constexpr ll LINF = 1001001001001001001ll; constexpr ll MOD = (1) ? 998244353 : 1e9+7; constexpr int NIL = -1; constexpr int pm[2] = {1, -1}; constexpr int dy[8] = {0, 1, 1, 1, 0, -1, -1, -1}; constexpr int dx[8] = {1, 1, 0, -1, -1, -1, 0, 1}; ll cel(ll a, ll b){ return (a + b - 1) / b;} ll Gcd(ll a, ll b){ return b ? Gcd(b, a % b) : abs(a);} template T powi(T x, ll exp){ return exp > 0 ? (exp & 1 ? x : 1) * powi(x * x, exp >> 1) : x / x; } ll modpow(ll x, ll exp, ll mod){ x %= mod; return exp > 0 ? (exp & 1 ? x : 1) * modpow(x * x, exp >> 1, mod) % mod : 1; } template bool chmin(T &a, T b){ return a > b ? (a = b, true) : 0;} template bool chmax(T &a, T b){ return a < b ? (a = b, true) : 0;} using Pair = pair; using Tpl = tuple; ll ExtGcd(ll a, ll b, ll &x, ll &y){ ll d = a; if(b != 0){ d = ExtGcd(b, a % b, y, x); y -= (a / b) * x; } else{ x = 1, y = 0; } return d; } pair ChineseRem(vec &b, vec &m) { ll r = 0, M = 1; for (int i = 0; i < (int)b.size(); ++i) { ll p, q; ll d = ExtGcd(M, m[i], p, q); // p is inv of M/d (mod. m[i]/d) if ((b[i] - r) % d != 0) return make_pair(0, -1); ll tmp = (b[i] - r) / d * p % (m[i]/d); r += M * tmp; M *= m[i]/d; } return mkpr((r % M + M) % M, M); } void Main(){ vec B(3), M(3); rep(i, 3) cin >> B[i] >> M[i]; auto ans = ChineseRem(B, M); if(ans.se == -1) cout << -1 << endl; else if(ans.fi != 0) cout << ans.fi << endl; else cout << ans.se << endl; } signed main(){ cin.tie(nullptr); ios_base::sync_with_stdio(false); cout << fixed << setprecision(10); Main(); return 0; }