#include <iostream>
using namespace std;

int main(){
   int n,exp = 0,ikeep,need = 3000000;
   cin >> n;
   int g[n],d[n];
   for(int i = 0;i < n;i++) cin >> g[i] >> d[i];
   for(int i = 0;i < n;i++){
      if(exp < g[i] - 30000 * d[i]){
         exp = g[i] - 30000 * d[i];
         ikeep = i + 1;
      }
   }
   if(need - 6 * exp <= 0){
      cout << "YES" << endl;
      for(int i = 0;i < 6;i++) cout << ikeep << endl;
   }else cout << "NO" << endl;
}