#include using namespace std; #pragma GCC optimize("Ofast") #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[8]={1,0,-1,0,1,1,-1,-1}; const ll dx[8]={0,1,0,-1,1,-1,1,-1}; template inline bool chmax(T &a, T b) { return ((a < b) ? (a = b, true) : (false)); } template inline bool chmin(T &a, T b) { return ((a > b) ? (a = b, true) : (false)); } const int mod = MOD; const int max_n = 200005; struct mint { ll x; // typedef long long ll; mint(ll x=0):x((x%mod+mod)%mod){} mint operator-() const { return mint(-x);} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;} mint operator+(const mint a) const { return mint(*this) += a;} mint operator-(const mint a) const { return mint(*this) -= a;} mint operator*(const mint a) const { return mint(*this) *= a;} mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } bool operator==(const mint &p) const { return x == p.x; } bool operator!=(const mint &p) const { return x != p.x; } // for prime mod mint inv() const { return pow(mod-2);} mint& operator/=(const mint a) { return *this *= a.inv();} mint operator/(const mint a) const { return mint(*this) /= a;} }; istream& operator>>(istream& is, mint& a) { return is >> a.x;} ostream& operator<<(ostream& os, const mint& a) { return os << a.x;} using vm=vector; using vvm=vector; struct combination { vector fact, ifact; combination(int n):fact(n+1),ifact(n+1) { assert(n < mod); fact[0] = 1; for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i; ifact[n] = fact[n].inv(); for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i; } mint operator()(int n, int k) { if (k < 0 || k > n) return 0; return fact[n]*ifact[k]*ifact[n-k]; } }comb(max_n); void solve(){ ll a,b,c;cin >> a >> b >> c; mint ans=0; vvm dp(110,vm(110));dp[1][1]=1; for(ll i=1;i<=a+1;i++){ for(ll j=1;j<=b+1;j++){ //cout << i <<" " << j << endl; if(i!=a+1&&j!=b+1){ for(ll k=1;k<=c;k++){ ans+=dp[i][j]*comb(a+1-i-1+k-1,k-1)*comb(b+1-j-1+c+1-k-1,c+1-k-1); //cout << comb(a+1-i-1+k-1,k-1)*comb(b+1-j-1+c+1-k-1,c+1-k-1) << endl; //cout << comb(a+1-i-1+k-1,k-1) <<" " << comb(b+1-j-1+c+1-k-1,c+1-k-1) << endl; } } else if(i==a+1&&j==b+1)continue; else if(i==a+1){ ans+=dp[i][j]*comb(b+1-j-1+c-1,c-1); } else if(j==b+1){ ans+=dp[i][j]*comb(a+1-i-1+c-1,c-1); } dp[i+1][j]+=dp[i][j]; dp[i][j+1]+=dp[i][j]; //cout << i <<" " << j <<" " << ans << endl; } } for(ll k=1;k<=c;k++){ for(ll l=k;l<=c;l++){ ans+=comb(k+a-2,a-1)*comb(c+1-l+b-2,b-1); } } /*rep(i,a+2){ rep(j,b+2){ cout << dp[i][j] <<" "; } cout << endl; }*/ //ans+=dp[a+1][b+1]; cout << ans << endl; } int main(){ ll t;cin >> t; while(t--){ solve(); } }