#include #include #include using namespace std; using namespace atcoder; using mint = modint998244353; #define rep(i,n) for (int i = 0; i < (n); ++i) #define Inf 1000000000 struct HLD{ vector sz,parent,depth,root,pos; vector arr; HLD(vector> &E){ sz.resize(E.size(),1); parent.resize(E.size(),0); depth.resize(E.size(),0); root.resize(E.size(),0); pos.resize(E.size(),0); dfs(0,-1,E); dfs2(0,-1,E,0); } void dfs(int now,int p,vector> &E){ parent[now] = p; if(p==-1){ depth[now] = 0; } else{ depth[now] = depth[p]+1; } for(int i=0;i> &E,int r){ pos[now] = arr.size(); arr.push_back(now); root[now] = r; int maxi = 0; int ind = -1; for(int i=0;i> query(int u,int v){ vector> ret; int t = 0; while(root[u]!=root[v]){ if(depth[root[u]] <= depth[root[v]]){ ret.insert(ret.begin()+t,{pos[root[v]], pos[v]}); v = parent[root[v]]; } else{ ret.insert(ret.begin()+t,{pos[u],pos[root[u]]}); u = parent[root[u]]; t++; } } ret.insert(ret.begin()+t,{pos[u],pos[v]}); return ret; } int lca(int u,int v){ for(;;v=parent[root[v]]){ if(pos[u]>pos[v])swap(u,v); if(root[u]==root[v])return u; } } int get_distance(int u,int v){ return depth[u] + depth[v] - 2 * depth[lca(u,v)]; } }; void dfs(int cur,vector> &E,vector &cs,string &S,vector &t,int cp){ if(S.size()==cp)return; int ii = -1; rep(i,E[cur].size()){ int to = E[cur][i]; if(cs[to]==S[cp]){ ii = to; break; } } if(ii==-1){ ii = E.size(); E.push_back(vector()); E[cur].push_back(ii); cs.push_back(S[cp]); } t.push_back(ii); dfs(ii,E,cs,S,t,cp+1); } void dfs(int cur,int p,vector> &E){ rep(i,E[cur].size()){ int to = E[cur][i]; dfs(to,cur,E); } if(p!=-1)E[cur].push_back(p); } int main(){ int N; cin>>N; vector S(N); rep(i,N){ cin>>S[i]; } vector T = S; int Q; cin>>Q; vector t(Q),x(Q); vector c(Q); rep(i,Q){ cin>>t[i]>>x[i]; x[i]--; if(t[i]==1){ cin>>c[i]; T[x[i]] += c[i]; } } vector> E(1); vector cs(1,'-'); vector> ind(N); rep(i,N){ vector tt; dfs(0,E,cs,T[i],tt,0); ind[i] = tt; } dfs(0,-1,E); HLD H(E); fenwick_tree F(E.size()+5); //cout<r)swap(l,r); ans += F.sum(l,r+1); } cout<