#include using namespace std; #define rep(i,n) for(int i = 0; i < (int)n; i++) #define FOR(n) for(int i = 0; i < (int)n; i++) #define repi(i,a,b) for(int i = (int)a; i < (int)b; i++) #define pb push_back #define m0(x) memset(x,0,sizeof(x)) #define fill(x,y) memset(x,y,sizeof(x)) #define bg begin() #define ed end() #define all(x) x.bg,x.ed //#define mp make_pair #define vi vector #define vvi vector #define vll vector #define vvll vector #define vs vector #define vvs vector #define vc vector #define vvc vector #define pii pair #define pllll pair #define vpii vector> #define vpllll vector> #define vpis vector> #define vplls vector> #define vpsi vector> #define vpsll vector> template void chmax(T &a, const T &b) {a = (a > b? a : b);} template void chmin(T &a, const T &b) {a = (a < b? a : b);} using ll = long long; using ld = long double; using ull = unsigned long long; const ll INF = numeric_limits::max() / 2; const ld pi = 3.1415926535897932384626433832795028; const ll mod = 998244353; int dx[] = {-1, 0, 1, 0, -1, -1, 1, 1}; int dy[] = {0, -1, 0, 1, -1, 1, -1, 1}; #define int long long template ostream& operator<<(ostream &os, pair p) { os << "{" << p.first << ", " << p.second << "}"; return os; } template ostream& operator<<(ostream &os, vector &vec) { int size_of_vector = (int)vec.size(); os << "{"; for(int i = 0; i < size_of_vector; i++) { os << vec[i]; if(i!=size_of_vector-1) os << ", "; } os << "}\n"; return os; } template ostream& operator<<(ostream &os, array ar) { os << "{"; for(int i = 0; i < N; i++) { os << ar[i]; if(i!=N-1) os << ", "; } os << "}"; return os; } template void dbg(T a) { cout << a << endl; } int powmod(int n, int m, int MOD) { int res = 1; while(m > 0) { if(m&1) res = (res*n)%MOD; n = (n*n)%MOD; m >>= 1; } return res; } void solve() { int k; cin >> k; vi d(k), l(k); FOR(k) cin >> d[i] >> l[i]; vi t(k); FOR(k) { vector> doubling(32, vector(7, -1)); rep(j, 7) doubling[0][j] = (j*10+d[i])%7; rep(j, 31) { rep(k, 7) { doubling[j+1][k] = doubling[j][doubling[j][k]]; } } int now = 0; rep(j, 32) { if(l[i]>>j & 1) { now = doubling[j][now]; } } t[i] = now; } // dbg(t); vi ten(k); FOR(k) { ten[i] = powmod(10, l[i], 7); } vvi dp(k+1, vi(7, 0)); dp[0][0] = 1; FOR(k) { rep(j, 7) { (dp[i+1][j] += dp[i][j]) %= mod; (dp[i+1][(j*ten[i]+t[i]) % 7] += dp[i][j]) %= mod; } } // dbg(dp); int ans = 0; rep(i, 7) (ans += dp[k][i] * i % mod) %= mod; // dbg(dp); cout << ans << endl; } signed main() { cin.tie(nullptr); ios::sync_with_stdio(false); solve(); return 0; }