#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
//using mint = modint1000000007;
//const int mod = 1000000007;
//using mint = modint998244353;
//const int mod = 998244353;
//const int INF = 1e9;
//const long long LINF = 1e18;
#define rep(i, n) for (int i = 0; i < (n); ++i)
#define rep2(i,l,r)for(int i=(l);i<(r);++i)
#define rrep(i, n) for (int i = (n-1); i >= 0; --i)
#define rrep2(i,l,r)for(int i=(r-1);i>=(l);--i)
#define all(x) (x).begin(),(x).end()
#define allR(x) (x).rbegin(),(x).rend()
#define endl "\n"
#define P pair<int,int>
template<typename A, typename B> inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; }
template<typename A, typename B> inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; }
long long op(long long a, long long b) { return a + b; }
long long e() { return 0; }
long long target;
bool f(long long v) { return v < target; }
int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	int n, l; cin >> n >> l;
	vector<long long>c(n);
	rep(i, n)cin >> c[i];
	vector< segtree<long long, op, e>>seg(n);
	rep(i, n) {
		segtree<long long, op, e>_seg(l + 1);
		seg[i] = _seg;
	}
	rrep(i, n) {
		if (i == n - 1) {
			rep(j, c[i] + 1) seg[i].set(j, 1);
		}
		else {
			rep(j, l + 1) {
				int mn = max(0LL, j - c[i]);
				int mx = j;
				auto get = seg[i + 1].prod(mn, mx + 1);
				seg[i].set(j, get);
			}
		}
	}
	/*rep(i, n) {
		rep(j, l + 1) {
			cout << seg[i].get(j) << " ";
		}
		cout << endl;
	}*/
	int q; cin >> q;
	long long mx = seg[0].get(l);
	while (q--) {
		long long k; cin >> k;
		if (mx < k) {
			cout << -1 << endl;
			continue;
		}
		vector<int>ans(n);
		int sz = l;
		rep(i, n - 1) {
			//cout << "?" << endl;
			int mn = max(0LL, sz - c[i]);
			target = k;
			int idx = seg[i + 1].max_right<f>(mn);
			//cout << mn << " " << idx << endl;
			long long get = seg[i + 1].prod(mn, idx);
			k -= get;
			ans[i] = sz - idx;
			sz = idx;
			if (k <= 0)break;
		}
		ans[n - 1] = sz;
		rep(i, n)cout << ans[i] << " ";
		cout << endl;
	}
	return 0;
}