"""
最初の①にかける時間を少なくした。その分、②により多くの時間がさける

①ランダムにステーションを配置して各惑星から最も近いステーションまでのコストの和が最小になる解を山登りで見つける
②次に２点swapでコストの和が最小になる道順を時間いっぱいまで山登りで探索
"""

from random import randint,shuffle,sample
from time import time

# ダイクストラ（惑星専用）
def dijkstra(start = 0, INF=10**20):
    from heapq import heappop, heappush
    d = [INF for i in range(len(G))]
    prev = [-1]*len(G)
    d[start] = 0
    que = []
    heappush(que, (0, start))
    while que:
        d_, v = heappop(que)
        if d[v] < d_: continue
        for u, c in G[v].items():
            if d[u] > d[v] + c:
                d[u] = d[v] + c
                prev[u] = v
                heappush(que, (d[u], u))
    return d,prev
  
# sからtまでの最短経路を復元
def recover_path(s,t):
  prev = PREV[s]
  path = [t]
  while prev[t] != -1:
    t = prev[t]
    path.append(t)
  return path[::-1]

# 道順を与えられたときに距離を返す
def calc_score(path):
  assert len(path) == N+1, "The length of path should be N+1"
  score = 0
  for i in range(N):
    score += D[path[i]][path[i+1]]
  return score

stime = time()
N,M = map(int,input().split())
AB = [tuple(map(int,input().split())) for _ in range(N)]
AB2 = {}
for a,b in AB:
  if a not in AB2:
    AB2[a] = set()
  AB2[a].add(b)
alpha = 5

res2 = 10**30
argmin = []
for itr in range(1000):
  CD = []
  for i in range(M):
    c,d = randint(0,999),randint(0,999)
    while c in AB2 and d in AB2[c]:
      c,d = randint(0,999),randint(0,999)
    CD.append((c,d))

  res = 0
  for a,b in AB:
    MIN = 10**20
    for c,d in CD:
      MIN = min(MIN,(c-a)**2+(d-b)**2)
    res += MIN
    
  if res < res2:
    res2 = res
    argmin = CD
    
CD = argmin

G = [{} for _ in range(N+M)]
for i in range(N+M-1):
  if i < N:
    x1,y1 = AB[i]
  else:
    x1,y1 = CD[i-N]
  for j in range(i+1,N+M):
    if j < N:
      x2,y2 = AB[j]
    else:
      x2,y2 = CD[j-N]
    
    dist = (x2-x1)**2 + (y2-y1)**2
    if i<N and j<N:
      dist *= alpha**2
    elif i<N or j<N:
      dist *= alpha
      
    G[i][j] = G[j][i] = dist
    
D = [[0]*(N+M) for _ in range(N+M)]
PREV = [[-1]*(N+M) for _ in range(N+M)]
for i in range(N+M):
  D[i],PREV[i] = dijkstra(i)
  
ans = list(range(1,N))
score = calc_score([0]+ans+[0])

# 初期解
for i in range(100):
  ans2 = ans[:]
  shuffle(ans2)
  score2 = calc_score([0]+ans2+[0])
  
  if score2 < score:
    score = score2
    ans = ans2
    
    #print(score)
    
# 2点swapで山登り
for itr in range(10**7):
  if time() - stime > 0.8:
    break
  i,j = sample(range(N-1),2)
  ans[i],ans[j] = ans[j],ans[i]
  
  score2 = calc_score([0]+ans+[0])
  
  if score2 < score:
    score = score2
    
  else:
    ans[i],ans[j] = ans[j],ans[i]

ans = [0]+ans+[0]
all_path = [ans[0]]
for i in range(N):
  s,t = ans[i],ans[i+1]
  path = recover_path(s,t)
  for j in range(len(path)-1):
    all_path.append(path[j+1])
    
#print(score)
#print(all_path)
for c,d in CD:
  print(c,d)
print(len(all_path))
for idx in all_path:
  if idx < N:
    t = 1
  else:
    t = 2
    idx -= N
    
  print(t,idx+1)