#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pll = pair<ll, ll>;
#define drep(i, cc, n) for (ll i = (cc); i <= (n); ++i)
#define rep(i, n) drep(i, 0, n - 1)
#define all(a) (a).begin(), (a).end()
#define pb push_back
#define fi first
#define se second

const ll MOD = 1000000007;
const ll MOD2 = 998244353;
const ll INF = 1LL << 60;
const ll N_MAX = 2e5;

ll pow_mod(ll x, ll n, ll mod){
    ll ret = 1;
    while(n > 0){
        if(n & 1) ret = (ret*x)%mod;
        x = x*x%mod;
        n >>=1;
    }
    return ret;
}

vector<vector<ll>> mul(vector<vector<ll>> A, vector<vector<ll>> B, ll mod){
    vector<vector<ll>> C((ll)A.size(), vector<ll>((ll)B[0].size(), 0));
    for(ll i=0; i<(ll)A.size(); i++){
        for(ll k=0; k<(ll)B.size(); k++){
            for(ll j=0; j<(ll)B[0].size(); j++){
                C[i][j] = (C[i][j]+A[i][k]*B[k][j])%mod;
            }
        }
    }

    return C;
}

vector<vector<ll>> mat_pow_mod(vector<vector<ll>> A, ll n, ll mod){
    ll siz = (ll)A.size();
    vector<vector<ll>> B(siz, vector<ll>(siz, 0));
    rep(i, siz) B[i][i] = 1;
    while(n > 0){
        if(n & 1) B = mul(B, A, mod);
        A = mul(A, A, mod);
        n >>= 1;
    }

    return B;
}

int main(){
    ll n, m;
    cin >> n >> m;

    vector<vector<ll>> A(2, vector<ll>(2, 0));
    A[0][0] = 1;
    A[0][1] = 1;
    A[1][0] = 1;
    A = mat_pow_mod(A, n-1, m);
    cout << A[1][0] << endl;
}