#include <bits/stdc++.h>

#include <variant>

#define rep2(i, k, n) for (i64 i = (i64)(k); i < (i64)(n); i++)
#define rep(i, n) rep2(i, 0, n)
#define all(x) begin(x), end(x)
#ifdef ENV_LOCAL
#define dump \
  if (1) cerr
#else
#define dump \
  if (0) cerr
#endif

using namespace std;
using namespace std::string_literals;

using i32 = int32_t;
using i64 = int64_t;
using f64 = double;
using f80 = long double;
using vi32 = vector<i32>;
using vi64 = vector<i64>;

// using namespace harudake;

i64 f(i64 i, i64 c) {
  i64 ans = 0;
  while (i > 0) {
    if (i % 10 == c) ++ans;
    i /= 10;
  }
  return ans;
}

constexpr i64 mul = 100000;
i64 solve_large(i64 r, i64 k, i64 c) {
  i64 ans = 0;
  for (i64 i = 0; i + mul < r; i += mul) {
    i64 v = f(i, c);
    i64 num = (i + mul - 1) / k - (i - 1) / k;
    ans += v * num;
  }
  i64 last = r / mul * mul;
  i64 lstart = (last + k - 1) / k * k;
  for (i64 i = lstart; i <= r; i += k) {
    ans += f(i / mul, c);
  }
  return ans;
}
i64 solve_small(i64 r, i64 k, i64 c) {
  i64 ans = 0;
  unordered_map<i64, i64> m;
  vi64 seq;
  m[0] = 0;
  seq.push_back(0);
  i64 num = k % mul;
  i64 coeff = 1;
  while (num <= r) {
    if (m.count(num) > 0) {
      break;
    }
    m[num] = coeff;
    seq.push_back(f(num, c));
    num += k;
    num %= mul;
    ++coeff;
  }
  i64 cycle = coeff - m[num];
  i64 beg = m[num];
  i64 d = r / k;
  if (d <= beg) {
    rep(i, d + 1) { ans += seq[i]; }
  } else {
    i64 c = (d - beg) / cycle;
    i64 r = (d - beg) % cycle;
    rep(i, beg) { ans += seq[i]; }
    rep2(i, beg, coeff) { ans += c * seq[i]; }
    rep2(i, beg, beg + r + 1) { ans += seq[i]; }
  }
  return ans;
}
i64 solve_naive_large(i64 r, i64 k, i64 c) {
  i64 ans = 0;
  for (i64 i = k; i <= r; i += k) {
    ans += f(i / mul, c);
  }
  return ans;
}
i64 solve(i64 r, i64 k, i64 c) {
  i64 s = solve_small(r, k, c);
  i64 l = solve_large(r, k, c);
  // i64 nl = solve_naive_large(r, k, c);
  // dump << s << " " << l << " " << nl << endl;
  return s + l;
}

int main() {
  ios::sync_with_stdio(false);
  cin.tie(nullptr);
  i64 t;
  cin >> t;
  rep(ccnt, t) {
    i64 l, r, k, c;
    cin >> l >> r >> k >> c;
    i64 ans = solve(r, k, c) - solve(l - 1, k, c);
    cout << ans << "\n";
  }
  return 0;
}