#include <bits/stdc++.h>
#include <random>
using namespace std;
//#include <atcoder/all>
//using namespace atcoder;
using ll = long long;
using vll = vector<ll>;
using vvll = vector<vll>;
using vvvll = vector<vvll>;
using vvvvll = vector<vvvll>;
using vvvvvll = vector<vvvvll>;
using vvvvvvll = vector<vvvvvll>;
using vb = vector<bool>;
using vvb = vector<vb>;
using vvvb = vector<vvb>;
using vvvvb = vector<vvvb>;
using vd = vector<double>;
using vvd = vector<vd>;
using vvvd = vector<vvd>;
using vvvvd = vector<vvvd>;
using vvvvvd = vector<vvvvd>;
#define all(A) A.begin(),A.end()
#define ALL(A) A.begin(),A.end()
#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)
using pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;

template<class T>
bool chmax(T& p, T q, bool C = 1) {
    if (C == 0 && p == q) {
        return 1;
    }
    if (p < q) {
        p = q;
        return 1;
    }
    else {
        return 0;
    }
}

template<class T>
bool chmin(T& p, T q, bool C = 1) {
    if (C == 0 && p == q) {
        return 1;
    }
    if (p > q) {
        p = q;
        return 1;
    }
    else {
        return 0;
    }
}

ll gcd(ll(a), ll(b)) {
    if (b == 0)return a;
    ll c = a;
    while (a % b != 0) {
        c = a % b;
        a = b;
        b = c;
    }
    return b;
}

ll mod = 1e9 + 7;
ll modPow(long long a, long long n, long long p = mod) {
    if (n == 0) return 1; // 0乗にも対応する場合
    if (n == 1) return a % p;
    if (n % 2 == 1) return (a * modPow(a, n - 1, p)) % p;
    long long t = modPow(a, n / 2, p);
    return (t * t) % p;
}








int main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);

    ll M = 2e5 + 1;
    ll N;
    cin >> N;
    vll R(M + 1, 0);
    vll A(N);
    rep(i, N) {
        cin >> A[i];
        R[A[i]] = 1;
    }
    ll an = 0;
    vll SR(M + 2, 0), SN(M + 2, 0);
    for (ll m = M; m > 0; m--) {
        SR[m] = SR[m + 1];
        SN[m] = SN[m + 1];
        if (R[m] == 1) {
            an += m * SN[m + 1];
            for (ll j = m; j <= M; j += m) {
                ll nj = min(j + m, M + 1);
                ll s = SR[j] - SR[nj];
                ll n = SN[j] - SN[nj];
                ll p = j * n;
                an -= (s - p);
            }
            SR[m] += m;
            SN[m] += 1;
        }
    }
    cout << an << endl;


}