#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
//using mint = modint1000000007;
//const int mod = 1000000007;
//using mint = modint998244353;
//const int mod = 998244353;
//const int INF = 1e9;
//const long long LINF = 1e18;
#define rep(i, n) for (int i = 0; i < (n); ++i)
#define rep2(i,l,r)for(int i=(l);i<(r);++i)
#define rrep(i, n) for (int i = (n-1); i >= 0; --i)
#define rrep2(i,l,r)for(int i=(r-1);i>=(l);--i)
#define all(x) (x).begin(),(x).end()
#define allR(x) (x).rbegin(),(x).rend()
#define endl "\n"
#define P pair<int,int>
template<typename A, typename B> inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; }
template<typename A, typename B> inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; }

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	int n; cin >> n;
	vector<long long>a(n);
	rep(i, n)cin >> a[i];
	sort(allR(a));
	long long ans = 0;
	int mx = 200000;
	int sq = 450;
	fenwick_tree<int> fw(mx + 1);
	vector<long long>sum(sq);
	rep(i, n) {
		ans += a[i] * (2 * i - n + 1);
		//rep(j, i) ans += a[i] * (a[j] / a[i]);
		if (a[i] < sq) ans += sum[a[i]];
		else {
			int sz = (mx + 1) / a[i] + 1;
			rep(j, sz) {
				int l = j * a[i];
				int r = min(mx + 1, l + (int)a[i]);
				ans += a[i] * i * fw.sum(l, r);
			}
		}
		fw.add(a[i], 1);
		rep2(j, 1, sq) sum[j] += (a[i] / j)*j;
	}
	cout << ans << endl;
	return 0;
}