#include <bits/stdc++.h>
using namespace std;

using ll = long long;
using ull = unsigned long long;
using ld = long double;
template<class t> using vc = vector<t>;
template<class t> using vvc = vc<vc<t>>;
using pi = pair<int,int>;
using vi = vc<int>;
using vvi = vvc<int>;

#define rep(i,a,b) for (ll i = a; i < b; i++)
#define irep(i,a,b) for (int i = a; i > b; i--)
#define print(n) cout << n << '\n'
#define pritn(n) print(n)
#define rup(a,b) (a+b-1)/b
#define input(A,N) rep(i,0,N) cin>>A[i]
#define chmax(a,b) a = max(a,b)
#define chmin(a,b) a = min(a,b)

ll calc(ll n,map<ll,int> &dd,set<ll> &ddd){
    ll aa = n;
    map<ll,int> d;
    ll m = sqrt(n);
    for(auto i:ddd){
        while(n%i==0){
            d[i] += 1;
            n /= i;
        }
        if(i>n) break;
        if (dd[n] != 0){
            ll ans = 1;
            for (auto itr:d){
                ans *= itr.second+1;
            }
            ans *= dd[n];
            dd[aa] = ans;
            return ans;
        }
    }
    if (n!= 1) d[n] += 1;
    ll ans = 1;
    for(auto itr:d){
        ans *= itr.second+1;
    }
    return ans;
}

void calcc(set<ll> &d,ll n){
    vc<ll> l(n,0);
    rep(i,2,n+1){
        if (l[i]) continue;
        d.insert(i);
        ll now = i;
        while (now<=n){
            l[now] = 1;
            now += i;
        }
    }
    d.size();
    return;
}
int main(){
    cout << fixed << setprecision(15);
    
    ll X;
    cin >> X;
    ll x = X/2;
    ll now = 100000;
    set<pair<ll,ll>> ans;
    map<ll,int> dd;
    set<ll> ddd;
    calcc(ddd,x);
    rep(i,1,x+1){
        ll j = X - i;
        ll a = i - calc(i,dd,ddd);
        ll b = j - calc(j,dd,ddd);
        if (now < abs(a-b)){
            continue;
        }else if (now>abs(a-b)){
            ans.clear();
            now  = abs(a-b);
        }
        ans.insert(pair<ll,ll>(i,j));
        if(i!=j){
            ans.insert(pair<ll,ll>(j,i));
        }
    }
    // auto g = [](pair<ll,ll> a,pair<ll,ll> b){return a<b;};
    // sort(ans.begin(),ans.end(),g);
    for (auto itr:ans){
        cout<<itr.first<<" "<<itr.second<<'\n';
    }

    //system("pause");
    return 0;
}