#include using namespace std; #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<> #define rev(x) reverse(x); using ll=long long; using vl=vector; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[9]={0,1,0,-1,1,1,-1,-1,0}; const ll dx[9]={1,0,-1,0,1,-1,1,-1,0}; template inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; } int main(){ ll n,a,b;cin >> n >> a >> b; vvl dp(100000,vl(2)); dp[0][0]=-b;dp[0][1]=b; rep(i,100000-1){ dp[i+1][0]=min(dp[i][0]+a-b,dp[i][1]-a-b); dp[i+1][1]=min(dp[i][0]-a+b,dp[i][1]+a+b); } if(100000>n){ cout << min(dp[n-1][0],dp[n-1][1]) << endl;return 0; } else{ ll x=(n-1)%6; ll dif=dp[606+x][0]-dp[600+x][0]; ll ans=(n-1-(600+x))/6*dif+dp[600+x][0]; ll ep=dp[606+x][1]-dp[600+x][1]; ll ret=(n-1-(600+x))/6*ep+dp[600+x][1]; cout << min(ans,ret) << endl; } }