#pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #include #include using namespace std; using namespace atcoder; typedef long long ll; #define rep(i, n) for (int i = 0; i < (int)(n); i++) #define repr(i, n) for (int i = (int)(n) - 1; i >= 0; i--) #define repk(i, k, n) for (int i = k; i < (int)(n); i++) #define all(v) v.begin(), v.end() #define mod1 1000000007 #define mod2 998244353 #define vi vector #define vs vector #define vc vector #define vl vector #define vvi vector> #define vvc vector> #define vvl vector> #define vvvi vector>> #define vvvl vector>> #define pii pair #define pil pair #define pli pair #define pll pair #define vpii vector> #define vpll vector> #define vvpii vector>> #define vvpll vector>> template void debug(T e){ cerr << e << endl; } template void debug(vector &v){ rep(i, v.size()){ cerr << v[i] << " "; } cerr << endl; } template void debug(vector> &v){ rep(i, v.size()){ rep(j, v[i].size()){ cerr << v[i][j] << " "; } cerr << endl; } } template void debug(vector> &v){ rep(i,v.size()){ cerr << v[i].first << " " << v[i].second << endl; } } template void debug(set &st){ for (auto itr = st.begin(); itr != st.end(); itr++){ cerr << *itr << " "; } cerr << endl; } template void debug(multiset &ms){ for (auto itr = ms.begin(); itr != ms.end(); itr++){ cerr << *itr << " "; } cerr << endl; } template void debug(map &mp){ for (auto itr = mp.begin(); itr != mp.end(); itr++){ cerr << itr->first << " " << itr->second << endl; } } void debug_out(){ cerr << endl; } template void debug_out(Head H, Tail... T){ cerr << H << " "; debug_out(T...); } ll op(ll a, ll b){ return a + b; } ll e(){ return 0LL; } int main(){ ll N,Q; cin >> N >> Q; vl A(N); rep(i,N) cin >> A[i]; vl L(Q); vl R(Q); vl X(Q); rep(i,Q){ cin >> L[i] >> R[i] >> X[i]; L[i]--; R[i]--; } vector> p(0); rep(i,N){ p.push_back(pll(A[i], i)); } rep(i,Q){ p.push_back(pll(X[i], i + N)); } sort(all(p)); segtree seg1(N + 3);//Aのほうが小さいとわかった箇所の値を保管する segtree seg2(N + 3);//seg1に何個値が埋まったかを保管する vl ans(Q); for (ll i = 0; i < N + Q; i++){ if (p[i].second < N){ seg1.set(p[i].second, A[p[i].second]); seg2.set(p[i].second, 1); } else{ ll x = p[i].second - N; ll sum1 = seg1.prod(L[x], R[x] + 1); ll sum2 = seg2.prod(L[x], R[x] + 1); ll seg_num = R[x] - L[x] + 1; ans[x] = sum1 + (seg_num - sum2) * X[x]; } } rep(i,Q){ cout << ans[i] << endl; } }