N, K = gets.split.map(&:to_i)
A = gets.split.map(&:to_i)

def dfs(i, e, min, max, sum, memo)
  if i == e
    if min == -1 && max == 1
      memo[3][sum] = true
    elsif min == -1
      memo[2][sum] = true
    elsif max == 1
      memo[1][sum] = true
    else
      memo[0][sum] = true
    end
  else
    dfs(i + 1, e, -1, max, sum - A[i], memo)
    dfs(i + 1, e, min, max, sum, memo)
    dfs(i + 1, e, min, 1, sum + A[i], memo)
  end
end

memo1 = Hash.new { |h, k| h[k] = {} }
memo2 = Hash.new { |h, k| h[k] = {} }

mid = N / 2
dfs(0, mid, 0, 0, 0, memo1)
dfs(mid, N, 0, 0, 0, memo2)

if A.count(K) > 0
  puts 'Yes'
  exit
end

if memo1[3][K] || memo2[3][K]
  puts 'Yes'
  exit
end

1.upto(3) do |t|
  memo1[t].each do |k, v|
    case t
    when 1
      if memo2[2][K - k] || memo2[3][K - k]
        puts 'Yes'
        exit
      end
    when 2
      if memo2[1][K - k] || memo2[3][K - k]
        puts 'Yes'
        exit
      end
    when 3
      if memo2[1][K - k] || memo2[2][K - k] || memo2[3][K - k]
        puts 'Yes'
        exit
      end
    end
  end
end

puts 'No'