# -*- coding: utf-8 -*-

from collections import Counter

s1 = input()
N = int(input())
s2 = input()

cs1 = Counter(s1)
cs2 = Counter(s2)

if cs1 != cs2:
    # カウンターが異なれば成功
    print('SUCCESS')
elif cs1['o'] * cs1['x'] == 0:
    # 以下はカウンターが等しいとき
    # すべて'o', すべて'x'ならすべてあり得るので失敗
    print('FAILURE')
else:
    # ('o', 'x') = (1, 2), (2, 1)のとき
    if N >= 2:
        print('FAILURE')
    elif N == 0:
        if s1 == s2:
            print('FAILURE')
        else:
            print('SUCCESS')
    else:
        # N == 1
        # 少ない方の文字を取得
        c = ''
        if cs1['o'] == 1:
            c = 'o'
        else:
            c = 'x'

        if s1.index(c) == s2.index(c) == 1:
            print('SUCCESS')
        elif s1.index(c) % 2 == 0 and abs(s1.index(c) - s2.index(c) == 2):
            print('SUCCESS')
        else:
            print('FAILURE')