#include <iostream>
#include <algorithm>
#include <iomanip>
#include <vector>
#include <queue>
#include <deque>
#include <set>
#include <map>
#include <tuple>
#include <cmath>
#include <numeric>
#include <functional>
#include <cassert>

#define debug_value(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << #x << "=" << x << endl;
#define debug(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << x << endl;

template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }

using namespace std;
typedef long long ll;

template<typename T>
vector<vector<T>> vec2d(int n, int m, T v){
    return vector<vector<T>>(n, vector<T>(m, v));
}

template<typename T>
vector<vector<vector<T>>> vec3d(int n, int m, int k, T v){
    return vector<vector<vector<T>>>(n, vector<vector<T>>(m, vector<T>(k, v)));
}

template<typename T>
void print_vector(vector<T> v, char delimiter=' '){
    if(v.empty()) {
        cout << endl;
        return;
    }
    for(int i = 0; i+1 < v.size(); i++) cout << v[i] << delimiter;
    cout << v.back() << endl;
}

int to_idx(char c){
    if(c == 'c') return 0;
    if(c == 'o') return 1;
    if(c == 'n') return 2;
    return 3;
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout << setprecision(10) << fixed;
    int n; cin >> n;
    string s; cin >> s;
    auto cnt = vec2d(3, 4, 0);
    for(int i = 0; i < 3*n; i++){
        cnt[i%3][to_idx(s[i])]++;
    }
    vector<int> mn(3, n);
    for(int i = 0; i < 3; i++){
        for(int j = 0; j < 3; j++){
            chmin(mn[i], cnt[j][(i+j)%3]);
        }
    }
    int ans = 0;
    auto ok = [&](int a, int b){
        if(a < 0 || b < 0) return false;
        int x = (a == 0 && b == 0) ? 0 : 1;
        if(mn[0]+a+b+x > n) return false;
        int y = b == 0 ? 0 : 1;
        if(mn[0]+a+b+y > n) return false;
        return true;
    };
    for(int i = 0; i < 2; i++){
        for(int j = 0; j < 2; j++){
            if(ok(mn[1]-i, mn[2]-j)) {
                chmax(ans, mn[0]+mn[1]+mn[2]-i-j);
            }
        }
    }
    cout << ans << endl;
}