#include using namespace std; //#pragma GCC optimize("O3") #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[9]={1,0,-1,0,1,1,-1,-1,0}; const ll dx[9]={0,1,0,-1,1,-1,1,-1,0}; template inline bool chmax(T &a, T b) { return ((a < b) ? (a = b, true) : (false)); } template inline bool chmin(T &a, T b) { return ((a > b) ? (a = b, true) : (false)); } int main(){ ll n,a,b;cin >> n >> a >> b; string s;cin >> s; vl v; ll cnt=0; s+="$$$$$$$$$$$$$$$$$$$$$"; rep(i,n+10){ if(s.substr(i,3)=="con"){ cnt++;i+=2; } else{ if(cnt)v.emplace_back(cnt);cnt=0; } } vl dp(n,-INF);//aをi回操作したときにbは何回操作できるか? dp[0]=0; for(auto p:v){ per(i,n){ if(dp[i]==-INF)continue; per(j,(p/a)+1){ ll f=(p-a*j)/b; if(i+jdp[i])chmax(ans,dp[i]*2+1); else chmax(ans,min(i,dp[i])*2); } cout << ans << endl; }