#include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; const int mod = 1000000007; struct mint { typedef long long ll; ll x; mint(ll x=0):x((x%mod+mod)%mod){} mint operator-() const { return mint(-x);} mint& operator+=(const mint a) { if ((x += a.x) >= mod) x -= mod; return *this; } mint& operator-=(const mint a) { if ((x += mod-a.x) >= mod) x -= mod; return *this; } mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;} mint operator+(const mint a) const { return mint(*this) += a;} mint operator-(const mint a) const { return mint(*this) -= a;} mint operator*(const mint a) const { return mint(*this) *= a;} mint pow(ll t) const { if (!t) return 1; mint a = pow(t>>1); a *= a; if (t&1) a *= *this; return a; } // for prime mod mint inv() const { return pow(mod-2);} mint& operator/=(const mint a) { return *this *= a.inv();} mint operator/(const mint a) const { return mint(*this) /= a;} }; istream& operator>>(istream& is, mint& a) { return is >> a.x;} ostream& operator<<(ostream& os, const mint& a) { return os << a.x;} int main() { int N, S, K; cin >> N >> S >> K; S -= K*N*(N-1)/2; if (S < 0) { printf("0\n"); return 0; } vector> dp(N+1, vector(S+1, 0)); dp[0][0] = 1; for (int i = 1; i <= N; i++) for (int j = 0; j <= S; j++) { if (j-i >= 0) dp[i][j] = dp[i-1][j] + dp[i][j-i]; else dp[i][j] = dp[i-1][j]; } printf("%lld\n", dp[N][S].x); return 0; }